Hint: ![\bf \begin{array}{llll} sin^{-1}[sin(whatever)]= whatever\\\\ cos^{-1}[cos(whatever)]= whatever\\\\ tan^{-1}[tan(whatever)]= whatever \end{array}\\\\ ------------------\\\\ \begin{array}{llll} sin[sin^{-1}(whatever)]= whatever\\\\ cos[cos^{-1}(whatever)]= whatever\\\\ tan[tan^{-1}(whatever)]= whatever \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bllll%7D%0Asin%5E%7B-1%7D%5Bsin%28whatever%29%5D%3D%20whatever%5C%5C%5C%5C%0Acos%5E%7B-1%7D%5Bcos%28whatever%29%5D%3D%20whatever%5C%5C%5C%5C%0Atan%5E%7B-1%7D%5Btan%28whatever%29%5D%3D%20whatever%0A%5Cend%7Barray%7D%5C%5C%5C%5C%0A------------------%5C%5C%5C%5C%0A%5Cbegin%7Barray%7D%7Bllll%7D%0Asin%5Bsin%5E%7B-1%7D%28whatever%29%5D%3D%20whatever%5C%5C%5C%5C%0Acos%5Bcos%5E%7B-1%7D%28whatever%29%5D%3D%20whatever%5C%5C%5C%5C%0Atan%5Btan%5E%7B-1%7D%28whatever%29%5D%3D%20whatever%0A%5Cend%7Barray%7D)
WILL GIVE BRAINLIEST 33 < m - 91
2 answers:
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Answer:
And we can find this probability using the complement rule and the normal standard table or excel:
The firgure attached illustrate the problem
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the retirement savings of a population, and for this case we know the distribution for X is given by:
Where and
We are interested on this probability
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And we can find this probability using the complement rule and the normal standard table or excel:
The firgure attached illustrate the problem
