√53 = 7.28
Therefore, it lies between 7 and 8.
If the zeros are r1,r2, ..., rn and the leading coefficient is a
then
p(x)=a(x-r1)(x-r2)....(x-rn)
Radius = √(7-(-1))² + (8-(-7))² = √8²+15² = √289 = 17
Let the point be (-15,y)
(-15-(-7))² + (y-(-1))² = 17²
⇒ -8² + (y+1)² = 17²
⇒ 64 + (y+1)² = 289
⇒ (y+1)² = 289 - 64 = 225
⇒ y+1 = +15 or -15
⇒ y = +15-1 or -15-1
⇒ y = 14 or -16
T<span>h</span>us, the point can be either (-15,14) or (-15,-16)
Well This is how you get a square to get the eligble answer so there.
