The general equation of line with the slope "m" and passing points (a,b) is :
y - b = m (x -a)
In the given question:
Slope m = -2, passing points (a,b) = (4,-4)
Substitute the value of a = 4, b = -4 in the general equation of line
The equation with the slope -2 and passing points (4,-4) is 2x + y = 4
Answer : 2x + y = 4
It is 16.256 because I went to google and found it.... yep that simple.
A) 6x -5y = 5
B) 3x + 5y = 4
Adding the equations:
9x = 9
x = 1
A) 6*1 -5y = 5
A) 6 - 5 = 5y
A) 5y = 1
y = 1/5 = .2
For the solid line it is (0,-3), (0,3), (-3,4)
for the dotted line it is (-1,-1), (-3,-2), (-3,2)
hope this helps don't know for sure though if its right i just did the best i could do.
To find the inverse, we swap the variables y and x, then solve for the new y.
3a.
Swapping the variables:
Solving for y:
The domain of this inverse is
.
3b.
Swapping:
Solving for y:
The domain of this inverse is
.
3c.
![y=\sqrt[3]{\frac{x-7}{3}}](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7B%5Cfrac%7Bx-7%7D%7B3%7D%7D)
Swapping:
![x=\sqrt[3]{\frac{y-7}{3}}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B%5Cfrac%7By-7%7D%7B3%7D%7D)
Solving for y:
The domain of this inverse is all real numbers.
4a.
,
4c.
,
![y=\sqrt[3]{\frac{(3x^3+7)-7}{3}} \\ y=\sqrt[3]{\frac{3x^3}{3}} \\ y=\sqrt[3]{x^3} \\ y=x](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B%283x%5E3%2B7%29-7%7D%7B3%7D%7D%20%5C%5C%20y%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3x%5E3%7D%7B3%7D%7D%20%5C%5C%20y%3D%5Csqrt%5B3%5D%7Bx%5E3%7D%20%5C%5C%20y%3Dx)
![y=3(\sqrt[3]{\frac{x-7}{3}})^3+7 \\ y = 3({\frac{x-7}{3}})+7 \\ y = (x-7)+7 \\ y=x](https://tex.z-dn.net/?f=y%3D3%28%5Csqrt%5B3%5D%7B%5Cfrac%7Bx-7%7D%7B3%7D%7D%29%5E3%2B7%20%5C%5C%20y%20%3D%203%28%7B%5Cfrac%7Bx-7%7D%7B3%7D%7D%29%2B7%20%5C%5C%20y%20%3D%20%28x-7%29%2B7%20%5C%5C%20y%3Dx)
