Identify the conic whose equation is given.
1 answer:
Answer:
Hyperbola
Step-by-step explanation:
The polar equation of a conic section with directrix ± d has the standard form:
r=ed/(1 ± ecosθ)
where e = the eccentricity.
The eccentricity determines the type of conic section:
e = 0 ⇒ circle
0 < e < 1 ⇒ ellipse
e = 1 ⇒ parabola
e > 1 ⇒ hyperbola
Step 1. <em>Convert the equation to standard form </em>
r = 4/(2 – 4 cosθ)
Divide numerator and denominator by 2
r = 2/(1 - 2cosθ)
Step 2. <em>Identify the conic </em>
e = 2, so the conic is a hyperbola.
The polar plot of the function (below) confirms that the conic is a hyperbola.
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Answer:
FIRST OPTION.
THIRD OPTION.
FOURTH OPTION.
FITH OPTION.
Step-by-step explanation:
The equation of the line in slope-intercept form is:
Where m is the slope, b the y-intercept and the exponent of x is always 1 or 0.
Solve for y from the equations shown below:
(In this linear function the slope is 0)
(It is a linear function)
(It is a linear function)
Equation of the line whose slope is not defined:
Answer:
Equation:
Step-by-step explanation:
Slope = 4/3
Y-intercept = -3
Therefore;
Equation: y = mx + b
Equation:
Hope this helps!