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Damm [24]
3 years ago
11

Suppose the population standard deviation is σ = 5 , an SRS of n = 100 is obtained, and the confidence level is chosen to be 98%

. The margin of error for estimating a mean μ is given by: 1.165. 0.1228. 1.228. 0.1165.
Mathematics
1 answer:
beks73 [17]3 years ago
6 0

Answer:

1.165.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.98}{2} = 0.01

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.01 = 0.99, so z = 2.33

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

In this problem, we have that:

\sigma = 5, n = 100. So

M = z*\frac{\sigma}{\sqrt{n}}

M = 2.33*\frac{5}{\sqrt{100}} = 1.165

So the correct answer is:

1.165.

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