Answer:
This contradicts the Mean Value Theorem since there exists a c on (1, 7) such that f '(c) = f(7) − f(1) (7 − 1) , but f is not continuous at x = 3
Step-by-step explanation:
The given function is

When we differentiate this function with respect to x, we get;

We want to find all values of c in (1,7) such that f(7) − f(1) = f '(c)(7 − 1)
This implies that;




![c-3=\sqrt[3]{63.15789}](https://tex.z-dn.net/?f=c-3%3D%5Csqrt%5B3%5D%7B63.15789%7D)
![c=3+\sqrt[3]{63.15789}](https://tex.z-dn.net/?f=c%3D3%2B%5Csqrt%5B3%5D%7B63.15789%7D)

If this function satisfies the Mean Value Theorem, then f must be continuous on [1,7] and differentiable on (1,7).
But f is not continuous at x=3, hence this hypothesis of the Mean Value Theorem is contradicted.
3 men
4 women
7 total
3 men/ 7 total = 198 men/ x total
using cross products
3*x = 7 * 198
divide each side by 3
x = 7*198/3
x = 462
There are 462 workers
If you mean 3 men and 1 women for a total of 4 workers when you state a ratio of men and women in a certain factory is 3 to 4.
3/4 =198/x
Using cross products
3x = 4* 198
Divide each side by 3
3x/3 = 4*198/3
x =264
264 workers
It all depends on how you define ratio of men and women in a certain factory is 3 to 4. This is incorrect phrasing and I took it to be men to women. You cannot have a ratio of men and women.
Answer:
316 eggs were spoiled.
Step-by-step explanation:
1020304 / 348 = 2931 remainder 316.
Answer: May you show the angle we are supposed to solve? its a bit unclear. or can you explain the angle to us?
Step-by-step explanation: