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viktelen [127]
2 years ago
13

anne has 24 more cards than devi. anne finds that 3/5 of devi's cards are equal to 1/2 of her cards. how many cards does anne ha

ve?
Mathematics
2 answers:
DochEvi [55]2 years ago
4 0
If 1/2 of 24 are 3/5 of devi's cards, then 1/2(24)=3/5x, 12=0.6x, 20=x. Devi has 20 cards

laila [671]2 years ago
3 0
Ok so A(Anne) = D(Devi) + 24
and 1/2A = 3/5D
which is equal to A = 6/5D
which means that the 1/5 extra must = 24
so A = 6*24 
 A = 144
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Answer:

1

Step-by-step explanation:

Firstly note that the graph is shifted up 2 units, as it starts at positive 2, when it should start at 0.

That only leaves choices 1 and 2

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5 0
3 years ago
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3 years ago
Help please i don’t understand
Monica [59]

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Triangles are similar ,

Thus :

\frac{9}{3}  =  \frac{6}{x}  \\

3 =  \frac{6}{x}  \\

\frac{6}{x}  = 3 \\

Inverse both sides

\frac{x}{6}  =  \frac{1}{3}  \\

Multiply sides by 6

6 \times  \frac{x}{6}  = 6 \times  \frac{1}{3}  \\

x = 2 \times 3 \times  \frac{1}{3}  \\

x = 2

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7 0
2 years ago
√48a^4 b^5 c^3 d simplify and keep it in radical form
Morgarella [4.7K]
I will assume the square root extends all the way across.

\sqrt{48a^4b^5c^3}

\sqrt{2^4\cdot3\cdot a^4b^5c^3}

\sqrt{(2^2)^2\cdot3\cdot(a^2)^2\cdot(b^2)^2\cdot b\cdot c^2\cdot c}

\sqrt{(4)^2\cdot3\cdot(a^2)^2\cdot(b^2)^2\cdot b\cdot c^2\cdot c}

\sqrt{(4\cdot a^2 \cdot b^2 \cdot c)^2\cdot3\cdot b\cdot c}

4\cdot a^2\cdot b^2\cdot c\sqrt{3\cdot b\cdot c}

\boxed{4a^2b^2c\sqrt{3bc}}






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3 years ago
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Answer:

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