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Wittaler [7]
2 years ago
9

Can you help me, please?

Mathematics
1 answer:
NemiM [27]2 years ago
8 0

Answer:

listen picture is not clear

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If a line passes thru the points (4,5) and (2,9) the slope of this line is
Allisa [31]

Answer:

m=-2

Explanation:

If a line passes through the points (4,5) and (2,9): to calculate the slope, use the formula below:

\text{Slope,m}=\frac{Change\text{ in y-axis}}{Change\text{ in x-axis}}

Substituting the points, we have:

\begin{gathered} m=\frac{9-5}{2-4} \\ =\frac{4}{-2} \\ =-2 \end{gathered}

The slope of this line is​ -2.

8 0
1 year ago
Help pls I got the other one wrong and my score went down :( PLS HELP ME NOW ITS PYTHAGOREAN THEOREM
vovangra [49]

Answer:

9.4

Step-by-step explanation:

We can use the Pythagorean theorem

a^2+b^2 = c^2 where a and b are the legs and c is the hypotenuse

5^2+8^2 = c^2

25 +64 = c^2

89 = c^2

Taking the square root of each side

sqrt(89) = sqrt(c^2)

9.433981132 = c

To the nearest tenth

9.4

5 0
3 years ago
Read 2 more answers
Sibal started with $500 in a bank account that does not earn interest. In the middle of every month, she withdraws 15 of the acc
Otrada [13]
After every month's withdrawals, 4/5 of the original amount at the start of the month will remain. The amount at the start of every month will change. Thus:
an = 4/5 (an-1) ; where a1 = 500.
4 0
3 years ago
For the triangle shown below, complete the following table.
Virty [35]

Answer:

See below ~

Step-by-step explanation:

<u>Sin A</u> : opposing side of ∠A / hypotenuse

  • <u>3/5</u>

<u>Sin C</u> : opposing side of ∠C / hypotenuse

  • <u>4/5</u>

<u></u>

<u>Cos A</u> : adjacent side of ∠A / hypotenuse

  • <u>4/5</u>

<u></u>

<u>Cos C</u> : adjacent side of ∠C / hypotenuse

  • <u>3/5</u>
6 0
2 years ago
If dy/dx = x(y-1), find the equation of the tangent line at x=-2 with f(-2)=3
Lapatulllka [165]

Answer:

The equation of the tangent line passing through the point (-2,3) is

 4 x + y +5 =0

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given that the slope of the tangent</em>

<em>              </em>m = \frac{dy}{dx} = x(y-1)<em></em>

<em>              m = -2( 3-1) = -4</em>

<em>Given point x = -2</em>

<em>          y = f(-2) =3</em>

<em>∴The given point ( x₁ , y₁) = ( -2 ,3)</em>

<u><em>Step(ii):-</em></u>

The equation of the tangent line passing through the point (-2,3)

y - y_{1} = m(x-x_{1} )

y -3 = -4(x-(-2))

y -3 = -4( x+2)

y-3 = -4x -8

4x + y -3+8=0

4x +y +5=0

<u><em>Step(iii):-</em></u>

<em>The equation of the tangent line passing through the point (-2,3) is</em>

<em>   4 x + y +5 =0</em>

<em></em>

3 0
3 years ago
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