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OlgaM077 [116]
4 years ago
12

simplify the expression. write the answer using scientific notation. (9x10^7)(7x10^9) 1.6x10^17 1.6x10^64 6.3x10^64 6.3x10^17

Mathematics
2 answers:
Daniel [21]4 years ago
5 0
The\ scientific\ notation:a\cdot10^n\ where\ 1\leq a \ \textless \  10\ and\ n\in\mathbb{Z}\\----------------------------\\\\(9\cdot10^7)(7\cdot10^9)=(9\cdot7)(10^7\cdot10^9)=63\cdot10^{7+9}\\\\=63\cdot10^{16}=6.3\cdot10^{16+1}=6.3\cdot10^{17}
kvasek [131]4 years ago
4 0

Answer:

6.3\times10^{17}

Step-by-step explanation:

We have to multiply the expression

(9\times10^7)\times(7\times10^9)

We can rewrite this multiplication as

(9\times7(10^7\times10^9)

Now, use the exponent rule, x^a\cdot x^b=a^{a+b}

63\times10^{7+9}\\\\=63\times10^{16}

Finally, write in scientific notation

6.3\times10^{17}

Last option is correct.

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valina [46]

The question is incomplete, the complete question is;

The radius of the sphere is 10 units.What is the approximate volume of the sphere? Use π = 3.14 and round to the nearest whole cubic unit. cubic units

Answer:

4187 cubic units

Step-by-step explanation:

According to the question;

radius (r) = 10 units

 π = 3.14

Volume of a sphere = 4/3*π*r^3

Substituting values;

V = 4/3*(3.14)*(10)^3

V = 4186.67 cubic units

V = 4187 cubic units (To the nearest whole cubic unit)

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3 years ago
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Jeff uses 3 fifth- size strips to model 3/5. he wants to use tenth size strips to models an equivalent fraction. how many tenth
Lapatulllka [165]
<span>To put the unknown in other words, we are to determine a fraction that has a denominator of 10 which should be equivalent to 3/5. If we let x be the numerator of the second fraction such that we form a proportion out of the two fractions that is,
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4 years ago
A probability experiment is conducted in which the sample space of the experiment is S 1,2,3,4, 5,6,7,8, 9, 10, 11, 12]. Let eve
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Answer:

E\ n\ F = \{1, 5, 6,7\}

F\ n\ G =\{9\}

F\ U\ G =\{1,5,6, 7, 8,9,10, 11, 12\}

P(F\ U\ G) = \frac{3}{4}

Step-by-step explanation:

Given

S = \{1,2,3,4, 5,6,7,8, 9, 10, 11, 12\}

E = \{1,2, 3, 4, 5, 6,7\}

F =\{1,5,6, 7, 8,9\}

G = \{9,10, 11, 12\}

H = \{2, 3, 4\}

Solving (5): E and F

Sets of E and F = E n F

E\ n\ F = \{1,2, 3, 4, 5, 6,7\}\ n\ \{1,5,6, 7, 8,9\}

List out common elements

E\ n\ F = \{1, 5, 6,7\}

<em>They are not mutually exclusive because </em>n(E\ n\ F) \neq 0<em />

Solving (6): F and G

Sets of F and G = F n G

F\ n\ G =\{1,5,6, 7, 8,9\}\ n\ \{9,10, 11, 12\}

List out common elements

F\ n\ G =\{9\}

<em>They are not mutually exclusive because </em>n(F\ n\ G) \neq 0<em />

Solving (7): F or G and P(F or G)

Sets of F or G = F U G

F\ U\ G =\{1,5,6, 7, 8,9\}\ U\ \{9,10, 11, 12\}

List all elements without repetition

F\ U\ G =\{1,5,6, 7, 8,9,10, 11, 12\}

Solving P(F U G)

P(F\ U\ G) = \frac{n(F\ U\ G)}{n(S)}

n(F\ U\ G) = 9

n(S) = 12

Hence;

P(F\ U\ G) = \frac{9}{12}

Divide by 3

P(F\ U\ G) = \frac{3}{4}

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Step-by-step explanation:

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