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kvasek [131]
3 years ago
12

X + 5 = 10 A) x = 2 B) x = 3 C) x = 4 D) x = 5

Mathematics
2 answers:
MrRa [10]3 years ago
8 0

D.) x = 5, because when you plug five in for x, 5 + 5 = 10 is correct.

Blababa [14]3 years ago
3 0

Hey there!

            \bold{x+5=10}

  1. \bold{A.)x=2}
  2. \bold{B.)x=3}
  3. \bold{C.)x=4}
  4. \bold{D.)x=5}

<h2>Okay, so first we have to do the <u><em>OPPOSITE</em></u> of \bold{addition} (which is \bold{subtraction})</h2><h3>So, \bold{subtract} by \bold{5} on each of the sides </h3>
  • \bold{x+5-5}  \bold{=10-5}
  • \bold{Cancel:5-5} because that gives you the result of \bold{0} which is <u><em>NOT</em></u> our answer
  • \bold{Keep:10-5} because it gives us the result your "\bold{x-term} "
  • \boxed{\boxed{\bold{Answer:x=5}}}

Good luck on your assignment and enjoy your day!


~\bold{LoveYourselfFirst:)}


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2 years ago
Two cables support a 800​-lb ​weight, as shown. Find the tension in each cable.
jeka94

Answer:

  • 892 lb (right)
  • 653 lb (left)

Step-by-step explanation:

The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...

  Rcos(45°) +Lcos(75°) = 800

  Rsin(45°) -Lsin(75°) = 0

Solving these equations by Cramer's Rule, we get ...

  R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))

     = 800sin(75°)/sin(120°) ≈ 892 . . . pounds

  L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds

The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.

_____

This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...

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2 years ago
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VladimirAG [237]

Answer:

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Step-by-step explanation:

\frac{1}{2} bh=bh\\\\\frac{1}{2}(8)(x+4)=3(x+6)\\4(x+4)=3x+18\\4x+16=3x+18\\4x=3x+2\\x=2

1. set the equation for the area of each shape equal to each other

2. simplify each side until you get 4x+16=3x+18

3. subtract 16 from both sides which will give you 4x=3x+2

4. subtract 3x from both sides which will give you the value of x. x=2

5. check that x=2 is correct by plugging it into the equations

triangle:

area=\frac{1}{2} (8)(2+4)\\area=4(6)\\area=24

rectangle:

area=3(2+6)\\area=3(8)\\area=24

the areas are the same

4 0
2 years ago
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