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Zina [86]
3 years ago
15

Help me with this one question plz i put a picture below so u can see it

Mathematics
1 answer:
Mkey [24]3 years ago
8 0
4 campers per one canoe

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Richard receives a paycheck twice each month. Here’s a copy of one of his pay statements. If there are 2 paydays per month, what
iogann1982 [59]
For the answer to the question above asking what is Richard’s monthly net income if <span>Richard receives a paycheck twice each month. Here’s a copy of one of his pay statements. If there are 2 paydays per month?
The answer for this is first solved for his Net Pay then you can multiply it by two so that you can get his monthly net income.</span>
3 0
3 years ago
250,000 grams is ________ kilograms. A) 0.25 B) 25 C) 250 D) 2500
alexira [117]
C) 250 is the right answer
3 0
3 years ago
Two mechanics worked on a car. The first mechanic worked for 5
ArbitrLikvidat [17]

<u>Answer:</u>

$50 and $115

<u>Step-by-step explanation:</u>

We know that,

the sum of the two rates = $165 per hour

Let x and (165 - x) represent the $/hour of the 15hr and 5hr mechanics respectively.

Then combining their charges together to get:

(x*15)hour+(165-x)*5 hour=1325

Solving for x to get:

15x-5x+825=1325

10x=500

x=50

So the rate charged per hour by one mechanic is $50 and for the other mechanic = (165-50)= $115.

8 0
3 years ago
The time intervals between successive barges passing a certain point on a busy waterway have an exponential distribution with me
lisov135 [29]

Answer:

a) <u>0.4647</u>

b) <u>24.6 secs</u>

Step-by-step explanation:

Let T be interval between two successive barges

t(t) = λe^λt where t > 0

The mean of the exponential

E(T) = 1/λ

E(T) = 8

1/λ = 8

λ = 1/8

∴ t(t) = 1/8×e^-t/8   [ t > 0]

Now the probability we need

p[T<5] = ₀∫⁵ t(t) dt

=₀∫⁵ 1/8×e^-t/8 dt

= 1/8 ₀∫⁵ e^-t/8 dt

= 1/8 [ (e^-t/8) / -1/8 ]₀⁵

= - [ e^-t/8]₀⁵

= - [ e^-5/8 - 1 ]

= 1 - e^-5/8 = <u>0.4647</u>

Therefore the probability that the time interval between two successive barges is less than 5 minutes is <u>0.4647</u>

<u></u>

b)

Now we find t such that;

p[T>t] = 0.95

so

t_∫¹⁰ t(x) dx = 0.95

t_∫¹⁰ 1/8×e^-x/8 = 0.95

1/8 t_∫¹⁰ e^-x/8 dx = 0.95

1/8 [( e^-x/8 ) / - 1/8 ]¹⁰_t  = 0.95

- [ e^-x/8]¹⁰_t = 0.96

- [ 0 - e^-t/8 ] = 0.95

e^-t/8 = 0.95

take log of both sides

log (e^-t/8) = log (0.95)

-t/8 = In(0.95)

-t/8 = -0.0513

t = 8 × 0.0513

t = 0.4104 (min)

so we convert to seconds

t = 0.4104 × 60

t = <u>24.6 secs</u>

Therefore the time interval t such that we can be 95% sure that the time interval between two successive barges will be greater than t is <u>24.6 secs</u>

6 0
3 years ago
A circle with its dimensions, in meters (m), is shown.
vesna_86 [32]

Answer:

84.78

Step-by-step explanation:

also if you dont mind giving me brainliest im trying to rank up, im 1 away. only if u dont mind

4 0
3 years ago
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