Given:
m∠B = 44°
Let's find the following measures:
m∠A, m∠BCD, m∠CDE
We have:
• m∠A:
Angle A and Angle B are interior angles on same side of a transversal.
The interior angles are supplementary.
Supplementary angles sum up to 180 degrees
Therefore, we have:
m∠A + m∠B = 180
m∠A + 44 = 180
Subtract 44 from both sides:
m∠A + 44 - 44 = 180 - 44
m∠A = 136°
• m,∠,BCD:
m∠BCD = m∠A
Thus, we have:
m∠BCD = 136°
• m∠CDE:
Angle C and angle CDE form a linear pair.
Linear pair of angles are supplementary and supplementary angle sum up to 180 degrees.
Thus, we have:
m∠D = m∠B
m∠D = 44°
m∠CDE + m∠D = 180
m∠CDE + 44 = 180
Subract 44 from both sides:
m∠CDE + 44 - 44 = 180 - 44
m∠CDE = 136°
ANSWER:
• m∠A = 136°
,
•
,
• m∠BCD = 136°
,
•
,
• m∠CDE = 136°
B will be your best answer
The amount of points increase ~20 points each hour
just look at the point placements, and the amount each point is worth
also note that the bottom is by half hours, not hours
hope this helps
Answer:
The number of times Ellis get to bat is 558.
Step-by-step explanation:
Here, let us assume the number of times Ellis bat = m
So, the number of times Dwight bat = 17 times fewer than Ellis
= m - 17
Also, number of times Wade got to bat = 10 more times than Dwight
= ( m- 17 )+ 10
Total number of bat times = 1650
So, the number of times ( Wade + Dwight + Ellis) bat together = 1650
⇒ ( m- 17 )+ 10 + (m - 17) + m = 1650
or, 3 m - 34 + 10 = 1650
or, 3 m = 1674
⇒ m = 1674/3 = 558 , or m = 558
Hence, the number of times Ellis get to bat = m = 558.
