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this is because there are 27 total students and 3 groups. let x represent the number of students per group. the equation would be 3(x)=27
if u need to solve for x, it would be x =9
Add 4x over to 14x, 3=5x2- 18x then add 18x to the other side 3+ 18x= 5x2then divided each side by 5,( 3+18x/5=x2) then square root each side the answer to x would be the square root of 3+18x/5
Since 4 is between 2 & 5 you input it into the middle equation.
x=4
so the answer is 4!
<span>Exactly 8*pi - 16
Approximately 9.132741229
For this problem, we need to subtract the area of the square from the area of the circle. In order to get the area of the circle, we need to calculate its radius, which will be half of its diameter. And the diameter will be the length of the diagonal for the square. And since the area of the square is 16, that means that each side has a length of 4. And the Pythagorean theorem will allow us to easily calculate the diagonal. So:
sqrt(4^2 + 4^2) = sqrt(16 + 16) = sqrt(32) = 4*sqrt(2)
Therefore the radius of the circle is 2*sqrt(2).
And the area of the circle is pi*r^2 = pi*(2*sqrt(2)) = pi*8
So the area of the rest areas is exactly 8*pi - 16, or approximately 9.132741229</span>
