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AlekseyPX
4 years ago
9

What is an armistice?

Mathematics
2 answers:
Alla [95]4 years ago
6 0

Answer: An armistice is a truce, typically used in wars to stop the fighting, battles, etc. Also a holiday in France.

ladessa [460]4 years ago
3 0

Answer:

An agreement made by opposing sides in a war to stop fighting for a certain time; a truce.

Step-by-step explanation: I just found this in google and decided to help. Hope it did :)

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Solve the system of equations<br>13х – 6у = 22<br><br> x=y+6​
Mrrafil [7]

Answer:

x = -2, y = -8

Step-by-step explanation:

13(y + 6) - 6y = 22

=> 13y + 78 - 6y = 22

=> 7y = -56

=> y = -8

x = -8 + 6

=> x = -2

4 0
3 years ago
1) What was an advantage the British forces had during the war?
krek1111 [17]
(I’m assuming this is the Revolutionary War)
1. They had a fully formed government and powerful empire
2. They were fighting in an area that was 3,000 miles away from their home country
3. They knew the layout of the land
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6 0
3 years ago
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Carol is driving at 25 km/h when she sees a stop light turn yellow. If it takes her 1.2 s to begin braking, and the car's accele
I am Lyosha [343]

Answer:

The total distance she travels from the time she first sees the light turn until the car stops is 6.02 meters

Step-by-step explanation:

The car when Carol begins to hit the brakes is traveling with constant deceleration, that means we have to use uniformly accelerated motion equations to solve for the distance traveled, but first we need to analyze the given data.

Given information

  • Initial velocity,  v_i = 25 km/h
  • Final velocity,  v_f = 0
  • Time, t = 1.2 s
  • Acceleration, a= -4.0 \cfrac{m}{s^2}

Almost all information is on standard units except the initial velocity, so we can convert it to meters per second.

v_i = 25 \cfrac{km}{h} \times \cfrac{1h}{3600s}\times \cfrac{1000m}{1km}\\v_i=6.94 \cfrac ms

Also notice that the final velocity is 0 m/s, since the car stops at the end.

Setting up the motion equation.

Since we have constant acceleration and since the goal is to find the distance we can use the following equation for uniformly accelerated motion.

v_f^2 = v_i^2 +2ad

Here d is the distance traveled, replacing the given information we get

0=\left(6.94 \cfrac ms\right)^2 +2\left( -4 \cfrac{m}{s^2}\right)d

Solving for d

We can solve for the distance traveled d by moving every other number to the other side.

-\left(6.94 \cfrac ms\right)^2 =2\left( -4 \cfrac{m}{s^2}\right)d

We can divide both sides by -8

\cfrac{6.94^2}{8} m= d

So we get

\boxed{d=6.02     m}

The car has traveled 6.02 meters before stopping.

3 0
3 years ago
PLEASE HELP ASAP ;-; !!!!!!! Sonya made a graph showing the first ten minutes of her drive to the movies.
victus00 [196]
It is option A because the car kept on increasing speed then did a Major speed increase then the line marks going in a constant speed

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6 0
4 years ago
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Algebra A is the midpoint of XY find XA,XY,and AY
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Idk look it up on google lol I just need the points to answer a question
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