Answer:
Quantity of heat needed (Q) = 722.753 × 10³
Step-by-step explanation:
According to question,
Mass of water (m) = 40 kg
Change in temperature ( ΔT) = 18°c
specific heat capacity of water = 4200 j kg^-1 k^-1
The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .
So, Heat (Q) = m×s×ΔT
Or, Q = 40 kg × 4200 × 18
or, Q = 3024 × 10³ joule
Hence, Quantity of heat needed (Q) = 3024 × 10³ joule
In calories 4.184 joule = 1 calorie
So, 3024 × 10³ joule = 722.753 × 10³
Your answer is 26,453
Although I don't feel as if this is a homework question, I will still show the work.
Work:
Step 1: 999 + 999 = 1,998
Step 2: 1,998 + 999 = 2,997
Step 3: 2,997 + 23,456 = 26,453
Hope I was able to help! :)
Answer:
-29
Step-by-step explanation:
they are both negative so u add them.
It is given that the triangle is isosceles right triangle . And in an isosceles right triangle the legs are equal . Let each leg be of x units. Now we use pythagorean identity, which is
So the length of each leg is 
