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Leviafan [203]
3 years ago
13

What is the solution of the equation ×-3=1/3×+5?

Mathematics
2 answers:
stira [4]3 years ago
6 0
X-3=(1/3)x+5
add 3 to both sides
x=(1/3)x+8
times 3 both sides ( we hates fractions)
3x=x+24
minus x both sides
2x=24
divide both sides by 2
x=12
murzikaleks [220]3 years ago
3 0
The Answer Is 14/15 Hope This Helps.
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In ΔJKL, l = 860 inches, j = 920 inches and ∠K=126°. Find ∠L, to the nearest degree.
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Answer:

26

Step-by-step explanation:

JKL= ABC,  jkl=abc

1.) use law of sines to find k.

c^{2} =a^{2} +b^{2} -2abCosC    

c=\sqrt{920^{2} +860^{2} -2(920)(860)cos(126) } = 1586.225515

2.) use law of cosines to find L

\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}  

plug in for b and c:  \frac{860}{sinB} =\frac{1586.225515}{sin126}

cross multiply: \frac{1586.23sinB}{1586.23} =\frac{860sin126}{1586.23}

sinB= 0.4386227612\\B=sin^-1(0.4386227612)= 26.01604086\\

L=26

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3 years ago
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guajiro [1.7K]
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Step-by-step explanation:

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3 0
3 years ago
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Step-by-step explanation:

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