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bearhunter [10]
3 years ago
11

Help me find the rule. Thank uuuuuu!!!!!

Mathematics
2 answers:
hoa [83]3 years ago
8 0

Answer:

It should be add 3 each time but I am not sure that 2 is right or not

Step-by-step explanation:

mylen [45]3 years ago
5 0

Answer:

y=3x+3

Step-by-step explanation:

You did the first box wrong. The 2 should be a 3.

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Find the consecutive positive odd integers whose product is 99​
dezoksy [38]

Answer:

9 and 11

Step-by-step explanation:

So let's say that the first integer is x.

That means that the second integer is x+2, since it us the next odd number.

This problem can be easily solved with our mind the answer is 9 and 11, but I'll show you the steps to slove this.

We make an equation using these two numbers:

(x)*(x+2)=99\\

Now all we gotta do is solve for x:

x^2 +2x = 99\\x^2+2x-99=0

Now we use either splitting the middle term or quadratic formula:

x^2+11x-9x+99=0\\x(x+11)-9(x+11)=0\\(x+11)(x-9)=0

Now we split each terma and solve for x:

(x-9)=0\\x=9\\(x+11)=0\\x=-11

Now the question states <em>positive </em>so we can rule out x = -11.

Now we have the first integer x = 9,

the second integer is x+2 = 9+2 =11

So the two consecutive positive odd integers are 9 and 11

4 0
3 years ago
Find the missing lengths:<br> LO=5 and OK=4, find OH and KH.
hodyreva [135]

Answer:

The length of KH is 6 units and OH is 6.3 units.

Step-by-step explanation:

Given the figure with lengths LO=5 and OK=4. we have to find the length of  OH and KH.

In ΔLOH

By Pythagoras theorem

LH^2=LO^2+OH^2\\\\LH^2=5^2+OH^2 → (1)

In ΔKOH,

KH^2=OH^2+OK^2\\\\KH^2=OH^2+4^2  → (2)

In ΔKHL,

KL^2=LH^2+KH^2

Using eq (1) and (2), we get

KL^2=5^2+OH^2+OH^2+4^2

9^2=25+2OH^2+16

⇒ 2OH^2=81-25-16=40

⇒ OH=\sqrt{20}=6.324\sim6.3units.

Put the above value in eq 2, we get

KH^2=20+4^2=36

⇒ KH=6 units.

8 0
4 years ago
Read 2 more answers
MINING A mine produces 42.5 tons of coal per hour. How much coal will the mine produce in 9.5 hours?
vladimir1956 [14]

Given

MINING A mine produces 42.5 tons of coal per hour.

Find out the how much coal will the mine produce in 9.5 hours.

To proof

As given in the question

A mine produces 42.5 tons of coal per hour i.e in the 1 hour mine produces the 42.5 tons .

Let us assume that the coal produce in the 9.5 hours be x.

than the equation becomes

x = 9.5 × 42.5

x =  403 . 75 tons

 403 . 75 tons coal will the mine produces in the 9.5 hours.

Hence proved








7 0
3 years ago
Read 2 more answers
Given f(x) = x + 9 and g(x) = x2 find (gºf)(x).
marissa [1.9K]

Answer:

g(f(x)) = (x + 9)^2 or x^2 + 18x + 81

Step-by-step explanation:

(gºf)(x) is the "c .... " of two functions f(x) and g(x):  f(x) is the input to g(x).

We start with g(x):  g(x) = x^2.  We replace the first x with f(x) and the second x with x + 9:

g(f(x)) = (x + 9)^2 or x^2 + 18x + 81

8 0
4 years ago
A market sells soup in 6-ounce cans and 12-ounce cans. On Tuesday, the market sold a total of 420 ounces of soup in 44 cans.
Vikki [24]

Answer:

The market sold 18 6-ounce cans of soup on Tuesday

Step-by-step explanation:

Let us solve the question

- The number of the 6-ounce cans is x

- The number of 12-ounce cans is y

- 6x + 12y = 420

→ Divide each term by 6 to simplify the equation

- x + 2y = 70 ⇒ (1)

- x + y = 44 ⇒ (2)

→ Subtract equation (2) from equation (1)

- (x - x) + (2y - y) = (70 - 44)

- 0 + y = 26

- y = 26

Substitute the value of y in equation (2) to find the value of x

-x + 26 = 44

→ Subtract 26 from both sides

- x + 26 - 26 = 44 - 26

- x = 18

- x represents the number of the 6-ounce cans

- The market sold 18 6-ounce cans of soup on Tuesday

8 0
3 years ago
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