.88y +.03y = final cost or more simply .91y = final cost
100% - 12% discount leaves 88% of y (.88y)
3% tax = .03y
.88y + .03y = .91y
The slope of the function is 2!
Answer:
-1/3 - (-3/5) = 4/15
Step-by-step explanation:
Reduce to simplest form
-1/3 - (-3/5)
= -1/3 + 3/5
Find the Lowest Common Multiple of 3 and 5
Lowest Common Multiple of 3and 5 is 15
Use the LCM to Simplify
= {(-5*1)+(3*3)} / 15
= (-5+9) / 15
= 4/15
Therefore,
-1/3 - (-3/5) = 4/15
Answer:
Number of week they have same amount = 4 week
Step-by-step explanation:
Given:
Amount Joe have = $14
Joe's saving per week = $10
Amount Josh have = $26
Josh saving per week = $7
Find:
Number of week they have same amount
Assume;
Number of week they have same amount = a
So,
(14 + 10a) = (26 + 7a)
3a = 12
a = 4
So,
Number of week they have same amount = 4 week
Using the binomial distribution, the probabilities are given as follows:
- 0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.
- 0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.
- Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.
<h3>What is the binomial distribution formula?</h3>
The formula is:


The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
The values of the parameters for this problem are:
n = 10, p = 0.4.
The probability that more than 4 weigh more than 20 pounds is:

In which:

Then:






Hence:


0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.
The probability that fewer than 3 weigh more than 20 pounds is:
P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0061 + 0.0403 + 0.1209 = 0.1673
0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.
For more than 7, the probability is:





Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.
More can be learned about the binomial distribution at brainly.com/question/24863377
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