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Alina [70]
3 years ago
15

Cuál enunciado No es verdadero con respecto al valor de la varieble n en la siguiente ecuación?

Mathematics
1 answer:
aliina [53]3 years ago
3 0

Answer:

es la c

Step-by-step explanation:

Explicación paso a paso:ya que para que de 0 tiene que ser un número negativo, tiene que ser el número inverso a 2/3, entonces n= -2/3 que tiene el mismo valor absoluto que  2/3

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Answer:

\displaystyle -20

Step-by-step explanation:

\displaystyle -9[5] + 3[7] + 4 = -45 + 21 + 4 = -20

I am joyous to assist you anytime.

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3 years ago
0 = 4x + 4 linear equation
FinnZ [79.3K]

Answer:

x = -1

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
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  5. Division
  6. Addition
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Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

0 = 4x + 4

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Subtract 4 on both sides:                    -4 = 4x
  2. Divide 4 on both sides:                        -1 = x
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2 years ago
HELP PLZZZSS EASYYYY 10 POINTS *easy*
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Answer:

A. 3:30.

Step-by-step explanation:

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Which of the following do you need to make a box &amp; whisker plot?
nikitadnepr [17]

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Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first the
Svetlanka [38]

Answer:

The hotel charge in each city before tax was <u>$5125</u> of the first city and <u>$3625</u> of the second city.

Step-by-step explanation:

Given:

A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first.

The tax of the first city was 6% and the tax of the second city was 10%.

Total hotel tax paid for two cities with $670.

Now, to find the hotel charge in each city before tax.

Let the hotel charge in first city before tax be x.

And the hotel charge in second city before tax be y.

<em>So, as the hotel charge of the second city was 1500 higher than the first.</em>

<em>Thus</em>,

y=x-1500   ........(1)

<em>And as given, the tax of the first city was 6% and the tax of the second city was 10%, total hotel tax paid for two cities with $670.</em>

6% of x + 10% of y = $670.

\frac{6x}{100} +\frac{10y}{100} =670

0.06x+0.10y=670

Substituting the value of y from equation (1) we get:

0.06x+0.10(x-1500)=670

0.06x+0.10x-150=670

0.16x-150=670

<em>Adding both sides by 150 we get:</em>

0.16x=820

<em>Dividing both sides by 0.16 we get:</em>

x=5125.

<em>The hotel charge in first city before tax = $5125.</em>

Now, substituting the value of x in equation (1) we get:

y=x-1500

y=5125-1500

y=3625.

<em>The hotel charge in second city before tax = $3625.</em>

Therefore, the hotel charge in each city before tax was $5125 of the first city and $3625 of the second city.

5 0
3 years ago
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