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2 years ago

Given b (x) = StartAbsoluteValue x + 4 EndAbsoluteValue, what is b (negative 10)?

Mathematics

2 answers:

jenyasd209 [6]2 years ago

6 0

Answer:

(6,+infinity)

Step-by-step explanation:

sorry wrong answer i got it wrong

dmitriy555 [2]2 years ago

4 0

Answer:

The answer is 6

Step-by-step explanation:

b(x) = |x+4|

b(-10) = |-10+4|

= |-6| (absolute value is always interested in +ve value)

= 6

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$\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}$

Step-by-step explanation:

1) Rewrite ${y}^{2}-2y+1y$ in the form ${a}^{2}-2ab+{b}^{2}$ , where a = y and b = 1.

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$\frac{y}{{(y-1)}^{2}}+\frac{6}{{y}^{2}+6y-7}$

3) Factor ${y}^{2}+6y-7$ .

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-1 and 7

2 - Rewrite the expression using the above.

$(y-1)(y-7)$

Outcome/Result: $\frac{y}{(y-1)^2} +\frac{6}{(y-1)(y+7)}$

4) Rewrite the expression with a common denominator.

$\frac{y(y+7)+6(y-1)}{{(y-1)}^{2}(y+7)}$

5) Expand.

$\frac{{y}^{2}+7y+6y-6}{{(y-1)}^{2}(y+7)}$

6) Collect like terms.

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7) Simplify ${y}^{2}+(7y+6y)-6y$ to ${y}^{2}+13y-6y$

$\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}$

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