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Nastasia [14]
2 years ago
12

Susanna can work 10 math problems in 15 minutes. How many can she work in an hour and a half?

Mathematics
2 answers:
shusha [124]2 years ago
7 0
Well this one is easy!
10 ~ 15
20 ~ 30
30 ~ 45
40 ~ 60
50 ~ 75
60 ~ 90
90 = 1 hour and 30 minutes! < 60 math problems.
docker41 [41]2 years ago
4 0
She can work 60 in an hour and a half. We find this by figuring out how many minutes are in an hour and a half (there are 90 minutes), dividing that number by 15 (which equals 6), and multiplying that number by 10 (which equals 60). 60 problems is the answer.
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A triangle has sides with lengths of 5x – 7,
Tom [10]

Answer:

10x - 17

Step-by-step explanation:

Perimeter is the sum of all sides

5x - 7 + (3x - 4) + (2x - 6)

10x - 7 - 4 - 6

10x - 17

4 0
3 years ago
Y=-1/3x^2-4x-5 in vertex form
grigory [225]

Answer:

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

Step-by-step explanation:

Given function:

Y=-\frac{1}{3}x^2-4x-5

We need to find the vertex form which is.,

y=a(x-h)^2+k

where (h,k) represents the co-ordinates of vertex.

We apply completing square method to do so.

We have  

Y=-\frac{1}{3}x^2-4x-5

First of all we make sure that the leading co-efficient is =1.

In order to make the leading co-efficient is =1, we multiply each term with -3.

-3\times Y=-3\times\frac{1}{3}x^2-(-3)\times4x-(-3)\times 5

-3Y=x^2+12x+15

Isolating x^2 and x terms on one side.

Subtracting both sides by 15.

-3Y-15=x^2+12x-15-15

-3Y-15=x^2+12x

In order to make the right side a perfect square trinomial, we will take half of the co-efficient of x term, square it and add it both sides side.  

square of half of the co-efficient of x term = (\frac{1}{2}\times 12)^2=(6)^2=36

Adding 36 to both sides.

-3Y-15+36=x^2+12x+36

-3Y+21=x^2+12x+36

Since x^2+12x+36 is a perfect square of (x+6), so, we can write as:

-3Y+21=(x+6)^2

Subtracting 21 to both sides:

-3Y+21-21=(x+6)^2-21

-3Y=(x+6)^2-21

Dividing both sides by -3.

\frac{-3Y}{-3}=\frac{(x+6)^2}{-3}-\frac{21}{-3}

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

8 0
3 years ago
There are 45 students who play a woodwind instrument in the school band. Of these, 18 play the saxophone. What percent of these
Mashutka [201]

Answer:

40% students play the saxophone.

Step-by-step explanation:

Given:

Total Number of students who play woodwind instrument = 45

Number of students who play saxophone = 18

We need to find the percent of students who play saxophone.

Solution:

Now we can say that;

To find the percent of students who play saxophone we will divide Number of students who play saxophone by Total Number of students who play woodwind instrument and the multiply by 100.

framing in equation form we get;

percent of students who play saxophone = \frac{18}{45}\times100= 40\%

Hence 40% students play the saxophone.

3 0
3 years ago
A certain 90-mile trip took 2 hours. Exactly 1/3 of the distance traveled was by rail and this part of the trip took 1/5 of the
antiseptic1488 [7]

The average rate, in miles per hour, of the rail portion of the trip is; D: 75

<h3>How to calculate the average speed?</h3>

Since exactly 1/3 of the distance travelled was by rail, then we can say that;

(1/3) * (90) = 30 miles

We are told that part of the trip took 1/5 of the travel time. Thus;

Time it takes to travel that distance is:

(1/5) * (2) = 2/5 of an hour

Average rate is;

30/(2/5) = 150/2 = 75 mph

Read more about Average speed at; brainly.com/question/4931057

#SPJ1

7 0
2 years ago
Convert the rectangular coordinates (-9, 3V3) into polar form. Express the angle
Whitepunk [10]

Answer:

(6\sqrt{3},\,\frac{5\pi}{6})

Step-by-step explanation:

The radius  r  can be found from the relationship

 r^2=x^2+y^2\\r^2=(-9)^2+(3\sqrt{3})^2\\r^2=81+27=108\\r=\sqrt{108}\\r=6\sqrt{3}

The point is in Quadrant II (-, +), so use the inverse cosine function to find the angle.

\cos{\theta}=\frac{x}{r}=\frac{-9}{6\sqrt{3}}\\\cos{\theta}=-\frac{9}{6\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}}\\\cos{\theta}=-\frac{9\sqrt{3}}{6\cdot3}\\\cos{\theta}=-\frac{\sqrt{3}}{2}\\\\\cos^{-1}\frac{-\sqrt{3}}{2}}=\frac{5\pi}{6}

See the attached image.

7 0
3 years ago
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