It's 4 and u should know that by now.
Answer:
Option B is correct
Function 1, because the slope is 4 and the slope of function 2 is 2.
Step-by-step explanation:
Slope-intercept form:
The equation of line is given by:

where, m is the slope and b is the y-intercept
As per the statement:
Function 1: y = 4x + 5
On comparing with [1] we have;
Slope of function 1 = 4
Function 2: The line passing through the points (1, 6) and (3, 10).
Using slope formula:

Substitute the given points we have;

⇒
Simplify:
⇒
⇒
⇒ Slope of the function 2 is, 2
Since, function 1 is greater rate of change.( i.e 4 > 2)
Therefore,
Function 1 has the greater rate of change, because the slope is 4 and the slope of function 2 is 2.
10 people who build at the same rate can frame a house in 6 days. That means it will take one person
days to finish the house.
Which means that it will take 4 people
days to finish the house.
So, the fractional part of the house 4 people can frame in 3 days will be 
Thus, Option D is the correct answer.
9514 1404 393
Answer:
(x, y) = (3, 12)
Step-by-step explanation:
Using the given variable definitions, we can write the equations ...
y = x + 9
2(x +y) = 30
__
Solving the second equation for y, we have ...
y = 15 -x
Substituting this into the first equation gives ...
15 -x = x +9
6 = 2x . . . . . . . . . add x-9
3 = x . . . . . . . . . . divide by 2
y = 3+9 = 12 . . . . substitute into the first equation
The numbers are (x, y) = (3, 12).
Answer:
![V = \left[\begin{array}{ccc}5&-1\end{array}\right]](https://tex.z-dn.net/?f=V%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%26-1%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
We want to reflect this 2x1 vector on the line y = x.
To make this reflection we must use the following matrix:
![R=\left[\begin{array}{cc}0&1\\1&0\\\end{array}\right]](https://tex.z-dn.net/?f=R%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0%261%5C%5C1%260%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Where R is known as the reflection matrix on the line x = y
Now perform the product of the vector <-1,5> x R.
![\left[\begin{array}{ccc}-1\\5\end{array}\right]x\left[\begin{array}{ccc}0&1\\1&0\end{array}\right]\\\\\\\left[\begin{array}{ccc}-1(0) +5(1)&-1(1)+5(0)\end{array}\right]\\\\\\\left[\begin{array}{ccc}5&-1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%5C%5C5%5Cend%7Barray%7D%5Cright%5Dx%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%261%5C%5C1%260%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%5C%5C%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%280%29%20%2B5%281%29%26-1%281%29%2B5%280%29%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%5C%5C%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%26-1%5Cend%7Barray%7D%5Cright%5D)
The vector matrix that represents the reflection of the vector <-1,5> across the line x = y is:
![V = \left[\begin{array}{ccc}5&-1\end{array}\right]](https://tex.z-dn.net/?f=V%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%26-1%5Cend%7Barray%7D%5Cright%5D)