If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:
... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)
... A = 440 yd²
Answer: y 12 6 4 3. - 2 Y x 1 | 2 | 3 | 4 |. | y | 7 | 5| 3 1. 3.
Step-by-step explanation:
Answer:
14 for x and 42 for y
Step-by-step explanation:
Answer:
x = 81
Steps:
It says that y ~ √x
We have points (9, 18) as a guide.
We can write y = f(x) = a√x +b
Use points (9, 18) as a guide
18 = a√9 +b
18 = 3a + b
One solution might be a = 6, which means f(x) = 6√x
Thus when y = 54,
54 = 6√x
9 = √x
81 = x
