Answer: There are 97 nickels and 108 quarters.
Step-by-step explanation:
Let x = Number of nickels, y = Number of quarters.
As per given,
x+y = 205 ...(i)
0.05x+0.25y = 31.85 ... (ii) [1 nickel = $0.05, 1 quarter = $ 0.25]
Multiply (ii) by 20, we get
x+5y=637 ...(iii)
Eliminate (i) from (iii)
4y = 432
⇒ y = 108 [Divide both sides by 4]
Put value of y in (i), we get
![108+x=205\Rightarrow\ x= 97](https://tex.z-dn.net/?f=108%2Bx%3D205%5CRightarrow%5C%20x%3D%2097)
Hence, there are 97 nickels and 108 quarters.
Answer:
what
Step-by-step explanation:
Answer:
![\frac{1}{3}(3x-5)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%283x-5%29)
Step-by-step explanation:
If you expand an equation you get its equivalent expression
True or False question, I would say that it's true.