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earnstyle [38]
3 years ago
14

I'm in a rush & I really need to solve these two problems:

Mathematics
1 answer:
Elenna [48]3 years ago
5 0
1. 23.5 x 2.3 = 54.05
when you are multiplying decimals you have to line up the decimal point.
example:
23.5
2.3

2. 12.34 x 4.321 = 53.32114
once again you need to line up your decimals when multiplying two decimals.
example: however I had to add a zero to the number 12.34 so everything would line up correctly. I hope you understand that.
12.340
4.321
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50 points for whoever answers the right answer
Olin [163]

Answer:

128

Step-by-step explanation:

Supplementary means they sum to 180, and it's also a straight line. 180-49 = 131. 131-3 = 128, or x.

6 0
2 years ago
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Emergency help please thank you
AlladinOne [14]

I would say the third asnwer, so 90 degrees :)

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3 years ago
Please help me with this problem please!!!!!!!!!!!!!!
777dan777 [17]

Answer:

Brain

Step-by-step explanation:

7 0
3 years ago
A group of 5 people goes to the theater. If each ticket costs $6.50, is $50 a reasonable estimate for the cost of 5 tickets ? Ex
MAVERICK [17]
No it is not because its more then ten numbers away from the solution of the five tickets
6 0
4 years ago
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Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). To estimate
yKpoI14uk [10]

Answer:

a) 0.5588

b) 0.9984

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 24

Standard Deviation, σ = 6.4

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}        

a) P(score between 20 and 30)

P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{6.4} \leq z \leq \displaystyle\frac{30-24}{6.4}) = P(-0.62 \leq z \leq 0.94)\\\\= P(z \leq 0.94) - P(z < -0.62)\\= 0.8264 - 0.2676 = 0.5588 = 55.88\%

P(20 \leq x \leq 30) = 55.88\%

b) Sampling distribution

Sample size, n = 22

The sample will follow a normal distribution with mean 24 and standard deviation,

s = \dfrac{\sigma}{\sqrt{n}} = \dfrac{6.4}{\sqrt{22}} =1.36

c) P(mean score of sample is between 20 and 30)

P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{1.36} \leq z \leq \displaystyle\frac{30-24}{1.36}) = P(-2.94 \leq z \leq 4.41)\\\\= P(z \leq 4.41) - P(z < -2.94)\\= 1 - 0.0016 = 0.9984 = 99.84\%

P(20 \leq x \leq 30) =99.84\%

5 0
4 years ago
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