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dem82 [27]
4 years ago
6

Bentley is at Sasha’s birthday party where there are 10 girls and 12 boys waiting for a turn to bob for apples. Sasha’s mom will

randomly select one person to be first. What is the probability that Bentley will be selected first?
Mathematics
1 answer:
klio [65]4 years ago
7 0

Answer:

The probability that Bentely will be selected first = 0.046

Step-by-step explanation:

The person will be randomly selected, it is not stated that sex is considered in the selection.

The total number of people present at the party = 10 + 12 = 22

The probability that Bentely will be selected first = 1/22

The probability that Bentely will be selected first = 0.046

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Explain: What is the solution to this system of equations? <br><br> 2x+y=20 <br> 6x-5y=12
bazaltina [42]

Answer:

solution set is (x,y) = (7,6)

Step-by-step explanation:

solving by substitution method

2x +y=20--------------1

6x-5y=12---------------2

from equation 1, solve for y

2x+y=20

y= 20-2x------equation 3

adding value of y in equation 2

6x-5y=12

6x-5(20-2x)=12

6x-100+10x=12

16x= 12+100

16x= 112

x= 112/16

x=7

adding value of x in equation 3

y= 20-2x

y= 20- 2(7)

y=20-14

y=6

so solution set (x,y) = (7,6)

3 0
3 years ago
Let T: Mmxn(R)Mmxn(R) be the function defined
alexandr402 [8]

Answer:

True. See the explanation and proof below.

Step-by-step explanation:

For this case we need to remeber the definition of linear transformation.

Let A and B be vector spaces with same scalars. A map defined as T: A >B is called a linear transformation from A to B if satisfy these two conditions:

1) T(x+y) = T(x) + T(y)

2) T(cv) = cT(v)

For all vectors x,y \in V and for all scalars c \in R. And A is called the domain and B the codomain of T.

Proof

For this case the tranformation proposed is t: M_{mxn} (R) > M_{nxm} (R)

Where T(A) = A^T

For this case we have the following assumption:

1) The transpose of an nxm matrix is an nxm matrix

And the following conditions:

2) T(A+B) = (A+B)^T = A^T + B^T = T(A) + T(B)

And we can express like this T(A+B) =T(A) + T(B)

3) If A \in M_{mxn}(R) and c \in R then we have this:

T(cA) = (cA)^T = cA^T = cT(A)

And since we have all the conditions satisfied, we can conclude that T is a linear transformation on this case.

5 0
3 years ago
Refer to the following scenario:You want to see if there is a difference between the exercise habits of Science majors and Math
bekas [8.4K]

Answer:

1. H0: P1 = P2

2. Ha: P1 ≠ P2

3. pooled proportion p = 0.542

4. P-value = 0.0171

5. The null hypothesis failed to be rejected.

At a signficance level of 0.01, there is not enough evidence to support the claim that there is significant difference between the exercise habits of Science majors and Math majors .

6. The 99% confidence interval for the difference between proportions is (-0.012, 0.335).

Step-by-step explanation:

We should perform a hypothesis test on the difference of proportions.

As we want to test if there is significant difference, the hypothesis are:

Null hypothesis: there is no significant difference between the proportions (p1-p2 = 0).

Alternative hypothesis: there is significant difference between the proportions (p1-p2 ≠ 0).

The sample 1 (science), of size n1=135 has a proportion of p1=0.607.

p_1=X_1/n_1=82/135=0.607

The sample 2 (math), of size n2=92 has a proportion of p2=0.446.

p_2=X_2/n_2=41/92=0.446

The difference between proportions is (p1-p2)=0.162.

p_d=p_1-p_2=0.607-0.446=0.162

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{82+41}{135+92}=\dfrac{123}{227}=0.542

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.542*0.458}{135}+\dfrac{0.542*0.458}{92}}\\\\\\s_{p1-p2}=\sqrt{0.001839+0.002698}=\sqrt{0.004537}=0.067

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.162-0}{0.067}=\dfrac{0.162}{0.067}=2.4014

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

\text{P-value}=2\cdot P(z>2.4014)=0.0171

As the P-value (0.0171) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

At a signficance level of 0.01, there is not enough evidence to support the claim that there is significant difference between the exercise habits of Science majors and Math majors .

We want to calculate the bounds of a 99% confidence interval of the difference between proportions.

For a 99% CI, the critical value for z is z=2.576.

The margin of error is:

MOE=z \cdot s_{p1-p2}=2.576\cdot 0.067=0.1735

Then, the lower and upper bounds of the confidence interval are:

LL=(p_1-p_2)-z\cdot s_{p1-p2} = 0.162-0.1735=-0.012\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= 0.162+0.1735=0.335

The 99% confidence interval for the difference between proportions is (-0.012, 0.335).

6 0
3 years ago
-2 ×^2 - 4y +6. x=-3. y=-2 <br> evaluate ​
gladu [14]

Answer:

<u><em>Answer is below</em></u>

Step-by-step explanation:

<em><u>-2 ×^2 - 4y +6</u></em>

<em><u>Evaluate simply means to form an idea of something</u></em>

<em><u>So Evaluate for x=−3,y=−2</u></em>

<em><u>−2(−3)2−(4)(−2)+6</u></em>

<em><u>−2(−3)2−(4)(−2)+6</u></em>

<em><u>Answer =−4</u></em>

8 0
3 years ago
POSSIBLE POINTS 125
Lena [83]

Answer:

$51.36

Step-by-step explanation:

48×7%

5 0
3 years ago
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