Question

For the function f(t) = Pe^rt, if P= 6 and r = 0.06, then what is the value of f(6) to the nearest tenth? A. 219.6 B. 8.6 C. 0.1 D. 2.2

Answer 1

B. 8.6 Let's substitute the given values into the function and calculate the result. So: f(t) = Pe^rt f(t) = 6e^0.06t f(6) = 6e^(0.06*6) f(6) = 6e^(0.36) f(6) = 6*1.433329415 f(6) = 8.599976487 Rounding to the nearest tenth, gives: 8.6 So the answer is "B. 8.6"