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Alona [7]
3 years ago
11

For the function f(t) = Pe^rt, if P= 6 and r = 0.06, then what is the value of f(6) to the nearest tenth? A. 219.6 B. 8.6 C. 0.1

D. 2.2
Mathematics
1 answer:
Ann [662]3 years ago
7 0
<span>B. 8.6 Let's substitute the given values into the function and calculate the result. So: f(t) = Pe^rt f(t) = 6e^0.06t f(6) = 6e^(0.06*6) f(6) = 6e^(0.36) f(6) = 6*1.433329415 f(6) = 8.599976487 Rounding to the nearest tenth, gives: 8.6 So the answer is "B. 8.6"</span>
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A manufacturer of running shoes knows that the average lifetime for a particular model of shoes is 15 months. Someone in the res
AveGali [126]

Answer:

The decision rule is  

Fail to reject the null hypothesis

 The conclusion is  

There is no sufficient evidence to show that  the  designer's claim of a better shoe is supported by the trial results.

Step-by-step explanation:

From the question we are told that

  The population mean is  \mu = 15 \ months

   The sample size is  n =  25

   The sample mean is  \= x  = 17 \ months

   The standard deviation is  s = 5.5 \ months

Let assume the level of significance of this test is  \alpha  = 0.05

    The null hypothesis is  H_o :  \mu = 15

     The alternative hypothesis is  H_a : \mu  > 17

Generally the degree of freedom is mathematically represented as  

         df = n -1

=>       df = 25 -1

=>       df = 24

Generally the test statistics is mathematically represented as

        t = \frac{\= x- \mu }{\frac{s}{\sqrt{n} } }

=>   t = \frac{ 17 - 15 }{\frac{5.5}{\sqrt{25} } }

=>   t =  1.8182

Generally from the student t distribution table the probability of obtaining   t =  1.8182 to the right of the curve at a degree of freedom of df = 24  is  

    p-value  = P(t > 0.18182 ) = 0.4286

From the value obtained we see that  p-value > \alpha hence

The decision rule is  

Fail to reject the null hypothesis

 The conclusion is  

There is no sufficient evidence to show that  the  designer's claim of a better shoe is  supported by the trial results.

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2 years ago
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rewona [7]

Answer:

C) The Spearman correlation results should be reported because at least one of the variables does not meet the distribution assumption required to use Pearson correlation.

Explanation:

The following multiple choice responses are provided to complete the question:

A) The Pearson correlation results should be reported because it shows a stronger correlation with a smaller p-value (more significant).

B) The Pearson correlation results should be reported because the two variables are normally distributed.

C) The Spearman correlation results should be reported because at least one of the variables does not meet the distribution assumption required to use Pearson correlation.

D) The Spearman correlation results should be reported because the p-value is closer to 0.0556.

Further Explanation:

A count variable is discrete because it consists of non-negative integers. The number of polyps variable is therefore a count variable and will most likely not be normally distributed.  Normality of variables is one of the assumptions required to use Pearson correlation, however, Spearman's correlation does not rest upon an assumption of normality. Therefore, the Spearman correlation would be more appropriate to report because at least one of the variables does not meet the distribution assumption required to use Pearson correlation.

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Answer:

w = 8

Step-by-step explanation:

–9 = –3(w − 5)

-3(w - 5) = -9

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Answer:

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