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yawa3891 [41]
3 years ago
14

If John has pairs 5 different colors pairs of socks, how many orders can he wear them in over five days? Repetition is not allow

ed because John puts his socks in the wash at the end of the day.
Mathematics
1 answer:
ikadub [295]3 years ago
4 0

Answer:

120 ways

Step-by-step explanation:

On the first day, John was 5 choices   5

On the second day he has 4 choices 4

On the third day he has 3 choices

On the fourth day he has 2 choices

On the fifth day he has 1 choice

5*4*3*2*1 = 120 different ways

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How many one-third packages can the worker make from 20 pounds of cookies?
andreev551 [17]

Answer: 60

Step-by-step explanation:

1/3 means 3 packages per 1 pound

3 x 20 + 60

5 0
3 years ago
Please help! thank you! :)
Anarel [89]

Answer:

(1,1)? Sorry im not completely sure

4 0
3 years ago
What is the answer to this??
Helga [31]

Since the triangle is equilateral, all its angles are equal to 60°

AO is the bisector⇒∠OAD = 30°

AO AO is the hypotenuse, ∠OAD = 30°⇒

OD=10:2=5ft

By the Pythagorean theorem

10^2=AD^2+5^2\\AD=\sqrt{100-25} \\AD=\sqrt{75}

AC=AD+DC=2\sqrt{75}=10\sqrt{3}

S=\frac{a^2\sqrt{3} }{4}

S=\frac{(10\sqrt{3})^2\sqrt{3}  }{4} =\frac{300\sqrt{3} }{4} =75\sqrt{3} ft^2

Answer: A) S=75\sqrt{3}ft²

P.S. Hello from Russia and sorry for my bad english :^)

5 0
3 years ago
The hypotenuse of a right triangle is 14 centimeters long. One of the legs of the triangle is 6 centimeters. What is the length
BartSMP [9]

Answer: 12.65 cm

Step-by-step explanation:

Use the Pythagoras theorem,

a^2 + b^2= c^2

You are given the hypotenuse , which is c and another leg which is either a or b, does not particularly matter- rearrange to find the missing length

c^2 - b^2 = a^2

14^2 - 6^2 = 160

Square root 160 to find the missing length

12.65

Hope this helped :)

5 0
3 years ago
What answer is this?
klemol [59]

Answer:

option B

\frac{31}{50}-\frac{4}{25} i

Step-by-step explanation:

Given in the question a complex fraction

<h3>Step1</h3>

To divide complex numbers, you must multiply by the conjugate. To find the conjugate of a complex number all you have to do is change the sign between the two terms in the denominator.

\frac{5+4i}{6+8i}(\frac{6-8i}{6-8i})

<h3>Step2</h3>

Distribute (or FOIL) in both the numerator and denominator to remove the parenthesis.

\frac{30+24i-40i-32i²}{36-64i^{2} }

<h3>Step3</h3>

Simplify the powers of i, specifically remember that i² = –1.

\frac{62-16i}{36+64}

<h3>Step4</h3>

\frac{62}{100}-\frac{16i}{100}

<h3>Step5</h3>

simply

\frac{31}{50}-\frac{4}{25}i

8 0
3 years ago
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