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bekas [8.4K]
4 years ago
6

use the frequency table to find the probability of at most 4 responses received to this week's newspaper editorials.

Mathematics
1 answer:
ZanzabumX [31]4 years ago
5 0

Answer:

B


Step-by-step explanation:

To get probability of AT MOST 4 responses means all the probabilities Equal to or Less Than 4.


<u>From the table, that is probability of 0, 1, 2, 3 or 4</u>. <em>(OR in probability means adding)</em>

<em>Hence, we add the number of editorials for P=0,1,2,3, and 4 and then divide by total number of editorials.</em>

P(\leq4)= \frac{20+30+56+38+34}{200}\\P(\leq4)=\frac{178}{200}\\P(\leq4)=0.89

Answer choice B is right.

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student tickets for the football game cost $12 each and adult ticket cost $20 $1,720 was collected for the 120 ticket sold at la
erik [133]

Answer:

85 student tickets and 35 adult tickets were sold.

Step-by-step explanation:

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We know that student tickets cost $12, adult ticket cost $20 and 120 tickets were sold.

So:

$12×A + $20×B = $1,720. Where A and B are the number of student tickets and adult tickets sold, respectively.

Given that 120 tickets were sold in total, we have that:

A + B = 120

So the system of equations to be solved is the following:

$12×A + $20×B = $1,720                    (1)

A + B = 120                                          (2)

Solving for 'A' in equation (2) we get:

A = 120 - B

Substituting this value into equation (1) we get:

$12×(120 - B) + $20×B = $1,720

Solving for 'B' we have:

$12×(120 - B) + $20×B = $1,720

$1,440 - $12×B + $20×B = $1,720

$1,440 + $8×B = $1,720

$8×B = $1,720 - $1,440

$8×B = $280

B = 35 tickets.

Given that B = 35, then A = 120 - 35 = 85 tickets.

So 85 student tickets and 35 adult tickets were sold.

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3 years ago
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Answer:

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Step-by-step explanation:

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