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3 years ago

12

X=_? please help. this assignment makes no sense and i cant find any helpful videos.

1 answer:

Elina [12.6K]3 years ago

7 0

See "intersecting secants theorem" (you should be able to find a variant that specifically applies to arc measures). It says that for this circle,

$30^\circ=\dfrac{x-40^\circ}2\implies x=100^\circ$

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Examine the graph at right. Then, in a sentence or two, suggest reasons why the graph rises at 11:00am and then drops at 1:15pm.

ArbitrLikvidat [17]

Based on the graph shown above, the graph rises at about 11:00 AM and drops again at 1:15 PM. The graph is Lacy's purse vs time, this means that the values involve money and time. The only reason that would explain the drop in value at 1:15 PM is that Lacy went to lunch and spent money.

3 0

3 years ago

Read 2 more answers

Can someone explain this to me.

almond37 [142]

Answer:

option D

$3*(\sqrt{x}+\sqrt{x-3})$

Step-by-step explanation:

Given in the question an expression,

$\frac{9}{\sqrt{x} -\sqrt{x-3}}$

Step 1

Divide and multiple by $\sqrt{x}+\sqrt{x-3}$ to remove radical sign from denominator.

$\frac{9}{\sqrt{x} -\sqrt{x-3}}*\frac{\sqrt{x} +\sqrt{x-3}}{\sqrt{x} +\sqrt{x-3}}$

Step 2

Apply a² - b² = (a+b)(a-b)

$\frac{9*\sqrt{x}+\sqrt{x-3}}{\sqrt{x^{2}}-\sqrt{(x-3)^{2}}}}$

Step 3

$\frac{9*\sqrt{x}+\sqrt{x-3}}{x-x+3}$

Step 4

$\frac{9*\sqrt{x}+\sqrt{x-3}}{3}$

Step 5

$3*(\sqrt{x}+\sqrt{x-3})$

7 0

3 years ago

What is the slope-intercept equation of the line below?

Oksi-84 [34.3K]

Answer:

C. y=4/5x-2

Step-by-step explanation:

7 0

3 years ago

What is the sum of 27 and r

Fudgin [204]

Answer:

27+r

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Passing through (-2,1 ) and perpendicular to<br> 4x + 7y + 3 = 0.

Lunna [17]

Answer:

<h2>7x - 4y + 18 = 0</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

========================================

Let

$k:y=m_1x+b_1\\\\l:y=m_2x+b_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\l\ \parallel\ k\iff m_1=m_2$

========================================

We have the equation of a line in a general form (Ax + By + C = 0)

Convert it to the slope-intercept form:

$4x+7y+3=0$ <em>subtract 7y from both sides</em>

$4x+3=-7y$ <em>divide both sides by (-7)</em>

$-\dfrac{4}{7}x-\dfrac{3}{7}=y\to m_1=-\dfrac{4}{7}$

Therefore

$m_2=-\dfrac{1}{-\frac{4}{7}}=\dfrac{7}{4}$

We have the equation:

$y=\dfrac{7}{4}x+b$

Put the coordinates of the point (-2, 1) to the equation, and solve for <em>b</em> :

$1=\dfrac{7}{4}(-2)+b$

$1=-\dfrac{7}{2}+b$ <em>multiply both sides by 2</em>

$2=-7+2b$ <em>add 7 to both sides</em>

$9=2b$ <em>divide both sides by 2</em>

[te]x\dfrac{9}{2}=b\to b=\dfrac{9}{2}[/tex]

Finally:

$y=\dfrac{7}{4}x+\dfrac{9}{2}$ - <em>slope-intercept form</em>

Convert to the general form:

$y=\dfrac{7}{4}x+\dfrac{9}{2}$ <em>multiply both sides by 4</em>

$4y=7x+18$ <em>subtract 4y from both sides</em>

$0=7x-4y+18$

6 0

3 years ago