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Allisa [31]
3 years ago
6

What is 2 and 1/2 divided into 3/4

Mathematics
2 answers:
jasenka [17]3 years ago
8 0

Answer:

3 1/3

Step-by-step explanation:

2 and 1/2 = 2 1/2.

2 1/2 = 5/2.

5/2 = 10/4.

10/4 ÷ 3/4 = 3.333333333333333333333333333333333333333333333333333333 and goes on forever, so we change it to a fraction.

Final answer: 3 1/3

hope this helps :)

Fed [463]3 years ago
5 0
It would be 3 and 1/3
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Rewrite the following integral in spherical coordinates.​
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correspond to the upper and lower halves of a sphere with radius \sqrt2. In spherical coordinates, this sphere is \rho=\sqrt2.

1 \le r \le \sqrt2 means our region is between two cylinders with radius 1 and \sqrt2. In spherical coordinates, the inner cylinder has equation

x^2+y^2 = 1 \implies \rho^2\cos^2(\theta) \sin^2(\phi) + \rho^2\sin^2(\theta) \sin^2(\phi) = \rho^2 \sin^2(\phi) = 1 \\\\ \implies \rho^2 = \csc^2(\phi) \\\\ \implies \rho = \csc(\phi)

This cylinder meets the sphere when

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which occurs at

\csc(\phi) = \sec(\phi) \implies \tan(\phi) = 1 \implies \phi = \dfrac\pi4+n\pi

where n\in\Bbb Z. Then \frac\pi4\le\phi\le\frac{3\pi}4.

The volume element transforms to

dx\,dy\,dz = r\,dr\,d\theta\,dz = \rho^2 \sin(\phi) \, d\rho \, d\theta \, d\phi

Putting everything together, we have

\displaystyle \int_0^{2\pi} \int_1^{\sqrt2} \int_{-\sqrt{2-r^2}}^{\sqrt{2-r^2}} r \, dz \, dr \, d\theta = \boxed{\int_0^{2\pi} \int_{\pi/4}^{3\pi/4} \int_{\csc(\phi)}^{\sqrt2} \rho^2 \sin(\phi) \, d\rho \, d\phi \, d\theta} = \frac{4\pi}3

4 0
2 years ago
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6 0
3 years ago
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Answer:

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3 years ago
A bag contains white matarles and red marables,126 in total.The number of whit marables is 6 more than 5 than 5 times the number
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Step-by-step explanation:

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Please show work for both problems
kirill [66]

Answer:

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Step-by-step explanation:

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x = 15

Plug 15 into both equations

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+ 10       + 10                         Add 10 to both sides

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Plug 12 into both equations

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