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bixtya [17]
3 years ago
15

Find the circumference of a circle with an area of 615.75 square inches

Mathematics
1 answer:
padilas [110]3 years ago
3 0

Answer:

C ≈ 87.96in

Step-by-step explanation:

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What is the factored form of 125a6-64?
iogann1982 [59]

Answer:

(5a^2-4)*(25a^4+20a^2+16)

Step-by-step explanation:

7 0
3 years ago
Phones-R-Us charges $16.95 per month and $0.05 per text message. Awesome Wireless charges $22.95 per
Dima020 [189]

Answer:

S \leq 200

Step-by-step explanation:

Given

Phone R-Us= $16.95 + $0.05 per SMS

Awesome Wireless = $22.95 + $0.02 per SMS

Required

Determine the number of SMS such that Awesome Wireless is greater or equal to Phone R-Us

Represent the SMS with S

For Phone R-Us, we have:

SMS = 16.95 + 0.05S

For Awesome Wireless, we have:

SMS = 22.95 + 0.02S

For Awesome Wireless is greater or equal to Phone R-Us, we have:

22.95 + 0.02S \geq 16.95 + 0.05S

Collect Like Terms

0.02S - 0.05S \geq 16.95 - 22.95

-0.03S \geq -6

Solve for S

\frac{-0.03S}{-0.03} \geq \frac{-6}{-0.03}

S \leq 200

<em>Hence: for Awesome Wireless to cost more or equal to Phone R-Us, the number of SMS must not exceed 200</em>

4 0
3 years ago
Find the length of side a.<br> 5<br> 3<br> O A. 16<br> O B. 34<br> O c. 2<br> O D. 4
xxMikexx [17]

Answer:

D

Step-by-step explanation:

a=\sqrt{c^{2} -b^{2} }

\sqrt{5^{2} -3^{2} } =4

a=4

5 0
2 years ago
Moon Sporting Goods received a shipment of tennis rackets and marked them up 45%. The cost of the tennis rackets to Moon was $85
Komok [63]

Answer:

$123.25

Step-by-step explanation:

A selling price reflecting a 45% markup can be found by multiplying the wholesale price ($85) by (1 + 0.45), or  1.45:

1.45($85) = $123.25

4 0
3 years ago
Given the following sets:
hjlf
<h3>Answer:  10</h3>

===========================================================

Explanation:

Even though your teacher doesn't want you to list the items of the set, it helps to do so.

We'll be working with these two sets

A = {b, d, f, h, j, I, n, p, r, t}

C =  {d, h, I, p, t}

When we union them together, we combine the two sets together. Think of it like throwing all the letters in one bin rather than two bins.

A u C = {b, d, f, h, j, I, n, p, r, t,   d, h, I, p, t  }

The stuff that isn't bolded is set A, while the stuff that is bolded is set C

After we toss out the duplicates, we end up with this

A u C = {b, d, f, h, j, I, n, p, r, t}

But wait, that's just set A. Notice how everything in set C can be found in set A. This indicates set C is a subset of set A.

That's why all of the stuff in bold was tossed out (because they were duplicates of stuff already mentioned).

Once we determine what set A u C looks like, we count out the number of items in that set to determine the final answer.

There are 10 items in {b, d, f, h, j, I, n, p, r, t} which means 10 is the final answer.

----------------------------

An alternative method is to use the formula below

n(A u C) = n(A) + n(C) - n(A and C)

n(A u C) = 10 + 5 - 5

n(A u C) = 10

The notation n(A and C) counts how many items are found in both sets A and C at the same time. But as mentioned earlier, this is identical to just counting how many items are in set C. So we'll have n(C) cancel out with itself.

In short, n(A u C) = n(A) = 10

8 0
2 years ago
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