Answer:
10
Step-by-step explanation
The earthquake measures 6.4 on the Richter scale which struck Japan in Jullu 2007 and caused and extensive damage. Earlier that year, a minor earthquake measuring 3.1 in the Richter scale has stroked in parts of Pennsylvania.
Fomular:
The magnitude of an earthquake is M log(I/S)
where I donates the intensity of the earthquake and S be the intensity of the standard earthquake.
Calculation:
Consider that M1 be the magnitude Japanese earthquake and M2 be the magnitude of the Pennsylvania earthquake and L1 be the intensity of the Japanese earthquake and L2 the intensity of the Pennsylvania earthquake.
Here the magnitude of the Japanese earthquake is M1 = 6.14 and the magnitude of the Pennsylvania is M2 = 3.1
By the use of magnitude of the earthquake fomular M = log I1/S, the intensity of the Japanese earthquake is calculated as follows .
M1 = log I1/S
I1/s = 10
The answer is 0.0016 or 0.0017
I don’t think so but divide the top one by the bottom one for every one of them and if it is all the same answer they are proportional x/y
