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2 years ago

PLEASE HELP!!!

Mathematics

1 answer:

Inessa [10]2 years ago

3 0

Answer:

Step-by-step explanation:

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Salma and coron broomall have reached an agreed upon price of $197,000. They plan to make a 30 percent down payment and finance

Sladkaya [172]

Answer:

1. The monthly payment is $689.5

2. The total amount to be paid is

$224,580.

Step-by-step explanation:

Salsa and Corn Broom all reached an agreement upon the price of $197,000.

- The plan on making a 30 percent down payment. This implies that the will pay 0.3 × $197,000 = $59,100

This leaves them with

$197,000 - $59,100

= $137,900 to pay.

The plan on financing this remaining amount at 6 percent for 20 years.

This means they will pay

0.06 × $137,900 = $8,274 for 20 years. This translates to the payment of $8,274 × 20 = $165,480 across the 20 years.

1. The monthly payment is the yearly payment divided by 12.

Which is $8,274 ÷ 12 = $689.5

2. The total amount to be paid is

$165,480 + $59,100

= $224,580.

6 0

3 years ago

An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

andrey2020 [161]

Answer:

The probability that A selects the first red ball is 0.5833.

Step-by-step explanation:

Given : An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

To find : What is the probability that A selects the first red ball?

Solution :

A wins if the first red ball is drawn 1st,3rd,5th or 7th.

A red ball drawn first, there are $E(1)= ^9C_2$ places in which the other 2 red balls can be placed.

A red ball drawn third, there are $E(3)= ^7C_2$ places in which the other 2 red balls can be placed.

A red ball drawn fifth, there are $E(5)= ^5C_2$ places in which the other 2 red balls can be placed.

A red ball drawn seventh, there are $E(7)= ^3C_2$ places in which the other 2 red balls can be placed.

The total number of total event is $S= ^{10}C_3$

The probability that A selects the first red ball is

$P(A \text{wins})=\frac{(^9C_2)+(^7C_2)+(^5C_2)+(^3C_2)}{^{10}C_3}$

$P(A \text{wins})=\frac{36+21+10+3}{120}$

$P(A \text{wins})=\frac{70}{120}$

$P(A \text{wins})=0.5833$

6 0

3 years ago

Hlppppppppppppppppppppppppppp

Assoli18 [71]

Answer:

B just did the test

Step-by-step explanation:

8 0

3 years ago

I need help with 25.

noname [10]

Sum of linear pair of angles = 180°

<EFG + <GFH = 180°

2n + 21 + 4n + 15 = 180°

6n + 36 = 180°

6n = 144

n = 24

<EFG = 2(24) + 21 = 69°

<GFH = 4n + 15 = 4(24) + 15 = 111°

6 0

3 years ago

True or False:

atroni [7]

Answer:

no it can't because

Step-by-step explanation:

coz the sum of any two angle should be greater than 3rd side

13 + 5 = 18 which is greater than 7
13 + 7 = 20 which is greater than 5
5 + 7 = 12 which is not greater than 13

so triangle cant be made

3 0

3 years ago