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11Alexandr11 [23.1K]
4 years ago
7

Elly and Drew work together to collect data to estimate the percentage of their classmates who own a particular brand of shoe. U

sing the same data, Elly will construct a 90 percent confidence interval and Drew will construct a 99 percent confidence interval. Which of the following statements is true?a. The midpoint of Elly's interval will be greater than the midpoint of Drew's interval. b. The midpoint of Elly's interval will be less than the midpoint of Drew's interval. c. The width of Elly's interval will be greater than the width of Drew's interval. d. The width of Elly's interval will be less than the width of Drew's interval. e. The width of Elly's interval will be equal to the width of Drew's interval
Mathematics
1 answer:
ladessa [460]4 years ago
4 0

Answer:

d. The width of Elly's interval will be less than the width of Drew's interval.

Step-by-step explanation:

The confidence level and the width of the confidence interval are direct proportional. This means that a confidence interval with a higher confidence level has a higher width.

For example, a 99 percent confidence interval is wider than a 90 percent confidence interval.

The midpoint of the confidence interval is the mean of the population, no matter the confidence level.

In this problem, we have that:

Elly: 90 percent CI

Drew: 99 percent CI

The correct answer is:

d. The width of Elly's interval will be less than the width of Drew's interval.

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Volgvan

Answer:

a) The calculated value   t =  5.903 > 2.572 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is a true mean value is less than 10

b) p - value  0.00001

The p - value 0.00001  < 0.01

The result is significant at p<0.01

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given mean of the population = 10

Sample size 'n'= 35

Mean of the sample x⁻ = 14.44

Standard deviation of the sample 's' = 4.45

Level of significance ∝ = 0.01

<u><em>Step(ii)</em></u>:-

<em>Null Hypothesis H₀</em> : μ >10

<em>Alternative Hypothesis</em> : H₁ : μ < 10

Test statistic

                 t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }

                t = \frac{14.44-10}{\frac{4.45}{\sqrt{35} } }

               t =  5.903

Degrees of freedom = n-1 = 35-1 = 34

tabulated value t₀.₀₁,₃₄  = 2.572

The calculated value   t =  5.903 > 2.572 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is a true mean value is less than 10

<u><em>p- value</em></u> :

p - value  0.00001

The p - value 0.00001  < 0.01

The result is significant at p<0.01

8 0
3 years ago
Help!!! Quick!!! Plzzzzz!!!
max2010maxim [7]

Answer:

x = -8

y = 9

Step-by-step explanation:

to solve this expression using simultaneous equation, we would say let

y =9............................................. equation 1

 6x + 5y =-3............................................equation 2

substitute equation 1 into equation 2

-3 = 6x + 5y............................................equation 2

6x + 5(9) = -3

6x + 45 = -3

collect the like terms

6x = -3-45

6x = -48

divide both sides by the coefficient of x which is 6

6x/6 = -48/6

x = -8

therefore y = 9

x = -8

4 0
3 years ago
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valentina_108 [34]

Answer:

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Answer:

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Step-by-step explanation:

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I got C 144. Use as a proportion and cross multiply.
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