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alexira [117]
4 years ago
14

(7x-y=7(x+2y=6 estimate the solution to the system of equations ​

Mathematics
1 answer:
jolli1 [7]4 years ago
8 0

Multiply the first equation by 2 to then use elimination by adding the 2 equations.

So, 14x-2y=14

+. x+2y=6

Equals 15x=20 so x=20/15=4/3

Plug in to first equation to get y

7(4/3)-y=7

28/3-y=7

28/3-y=21/3

So y=7/3

Plug both x and y into second equation to check

4/3+2(7/3)=

4/3+14/3=18/3=6 it works

So x=4/3, y=7/3

Hope this helps! Have a blessed day!

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Crazy boy [7]

:Answer:

You may want to use an online graphing calculator to help with this problem. :)



3 0
4 years ago
Forty percent of households say they would feel secure if they had $50,000 in savings. you randomly select 8 households and ask
Kay [80]

Answer:

Let X be the event of feeling secure after saving $50,000,

Given,

The probability of feeling secure after saving $50,000, p = 40 % = 0.4,

So, the probability of not  feeling secure after saving $50,000, q = 1 - p = 0.6,

Since, the binomial distribution formula,

P(x=r)=^nC_r p^r q^{n-r}

Where, ^nC_r=\frac{n!}{r!(n-r)!}

If 8 households choose randomly,

That is, n = 8

(a) the probability of the number that say they would feel secure is exactly 5

P(X=5)=^8C_5 (0.4)^5 (0.6)^{8-5}

=56(0.4)^5 (0.6)^3

=0.12386304

(b) the probability of the number that say they would feel secure is more than five

P(X>5) = P(X=6)+ P(X=7) + P(X=8)

=^8C_6 (0.4)^6 (0.6)^{8-6}+^8C_7 (0.4)^7 (0.6)^{8-7}+^8C_8 (0.4)^8 (0.6)^{8-8}

=28(0.4)^6 (0.6)^2 +8(0.4)^7(0.6)+(0.4)^8

=0.04980736

(c) the probability of the number that say they would feel secure is at most five

P(X\leq 5) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5)

=^8C_0 (0.4)^0(0.6)^{8-0}+^8C_1(0.4)^1(0.6)^{8-1}+^8C_2 (0.4)^2 (0.6)^{8-2}+8C_3 (0.4)^3 (0.6)^{8-3}+8C_4 (0.4)^4 (0.6)^{8-4}+8C_5(0.4)^5 (0.6)^{8-5}

=0.6^8+8(0.4)(0.6)^7+28(0.4)^2(0.6)^6+56(0.4)^3(0.6)^5+70(0.4)^4(0.6)^4+56(0.4)^5(0.6)^3

=0.95019264

8 0
3 years ago
Pls help me!!!!!! Its due tomorrow
prisoha [69]
Pls help its due tomorrow

3 0
3 years ago
What is the probability that a point chosen at random in the given figure will be inside the smaller square?
Aliun [14]
I have to interpret that:

1) the smaller square has side length = 3 cm

2) the bigger square has side length = 5 cm

3) the smaller square is completely inside the bigger square.

4) the points cannot be outside the bigger square



Under those assumptions the probability that a point is inside the smaller square  is

P (inside the smaller square) = area of the smaller square / area of the bigger square

P (inside the smaller squere) = (3cm)^2 / (5cm)^2 =  9 / 25


Answer: 9 / 25
8 0
3 years ago
What is a-5/6= -3 2/3 + 5/6
valentinak56 [21]

Answer:

A=-2

Step-by-step explanation:

iekdkdkdkdkdkdkdkdkkdd

3 0
3 years ago
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