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Tresset [83]
3 years ago
11

Determine the line that is perpendicular to y = 1/9x - 2/3

Mathematics
2 answers:
Hitman42 [59]3 years ago
4 0

Hello there,

determine the line that is perpendicular to y = 1/9x - 2/3

Answer: First choice(Option A)

ANTONII [103]3 years ago
3 0

Answer:

A

Step-by-step explanation:

Perpendicular lines have a relationship between their slopes. Their slope are negative inverses of each other. This means is one is 3 then the negative reciprocal is the other or -1/3. The slope here is 1/9 so the perpendicular slope is -9. Slope is always attached to the x term so A is the solution.

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Close! You forgot to square the 20!

6 0
3 years ago
Identify the value of b. PLEASE HELP!!
Degger [83]

Answer:

  b = 18

Step-by-step explanation:

From an external point, the products of distances to the near circle intercept and the far circle intercept are the same. For a tangent, such as AC, point A is both the near and far intercept point, so that product is the square of the length of AC.

  (AC)² = (CG)(CV)

  b² = 12·27 = 324 . . . . substitute known values

  b = √324 . . . . . . . . . . take the square root

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7 0
3 years ago
What is the area of this trapezoid?<br><br><br><br> Enter your answer in the box.<br><br> = cm²
VLD [36.1K]

A = 440

answer...

A

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6 0
3 years ago
Which shows a correct order to solve this story problem? Peter bought 3 biscuits for $1.59 each and 3 sausages for $2.50 each at
IceJOKER [234]
Since he bought more than one of each, he needs to find the total cost of the biscuits and sausage first.

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5 0
3 years ago
If the demand function for a commodity is given by the equation
Jet001 [13]

Answer:

q=26.92 p=31.13

Step-by-step explanation:

p^{2} +16q=1400\\\\q=\frac{1400-p^{2} }{16} ;\\\\700-p^{2} +10q=0\\\\q=\frac{p^{2}-700 }{10} ;\\\\

q=q\\\\\frac{1400-p^{2} }{16} =\frac{p^{2}-700 }{10} \\\\10(1400-p^{2})=16(p^{2}-700)\\\\14000-10p^{2}=16p^{2}-11200\\\\14000+11200=16p^{2}+10p^{2}\\\\25200=26p^{2}\\\\p^{2}=\frac{25200}{26} \\\\p=+\sqrt{\frac{25200}{26}} \\\\p=31.13

replace p in any equation and

q=\frac{1400-p^{2} }{16} \\\\q=\frac{1400-(31.13)^{2} }{16}\\\\q=26.92

3 0
4 years ago
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