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3 years ago

Determine the line that is perpendicular to y = 1/9x - 2/3

Mathematics

2 answers:

Hitman42 [59]3 years ago

4 0

Hello there,

determine the line that is perpendicular to y = 1/9x - 2/3

Answer: First choice(Option A)

ANTONII [103]3 years ago

3 0

Answer:

Step-by-step explanation:

Perpendicular lines have a relationship between their slopes. Their slope are negative inverses of each other. This means is one is 3 then the negative reciprocal is the other or -1/3. The slope here is 1/9 so the perpendicular slope is -9. Slope is always attached to the x term so A is the solution.

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Eloise started to solve a radical equation in this way: Square root of negative 2x plus 1 − 3 = x Square root of negative 2x plu

andreyandreev [35.5K]

Here I copy the steps and indicate where the error is.

Square root of negative 2x plus 1 − 3 = x=> this is the starting equation

√[ - 2x + 1] - 3 = x

Square root of negative 2x plus 1 − 3 + 3 = x + 3 in this step she added 3 to each side, which is fine

Square root of negative 2x plus 1 = x + 3 she made the addtions => fine

Square root of negative 2x plus 1 − 1 = x + 3 – 1 due to plus 1 in inside the square root, this step will not help

Square root of negative 2 x = x + 2 wrong! she cannot simplify - 1 that is out of the square root with +1 that is inside the square root

Then, from here on all is wrong, but she made other additional mistakes.

(Square root of negative 2 x)2 = (x − 4)2 −2x the right side should be (x+2)^2 which is x^2 + 4x +4 not (x-4)^2 - 2x

Later she made a mistake changing the sign of -8x to +8x

Those are the mistakes. Finally, the global error is that she should verify whether the found values satisfied the original equation.

3 0

3 years ago

Read 2 more answers

A sample of n = 4 scores is obtained from a population with a mean of 70 and a standard deviation of 8. If the sample mean corre

jeka57 [31]

Answer:

The value of the sample mean is 78.

Step-by-step explanation:

We are given that a sample of n = 4 scores is obtained from a population with a mean of 70 and a standard deviation of 8.

Also, the sample mean corresponds to a z score of 2.00.

Let $\bar X$ = sample mean

The z-score probability distribution for a sample mean is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean = 70

$\sigma$ = standard deviation = 8

n = sample size = 4

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, we are given that the sample mean corresponds to a z score of 2.00 for which we have to find the value of sample mean;

So, z-score formula is given by ;

z-score = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ = $\frac{\bar X-70}{\frac{8}{\sqrt{4} } }$

2.00 = $\frac{\bar X-70}{\frac{8}{\sqrt{4} } }$

2.00 = $\frac{\bar X-70}{4 } }$

$\bar X = 70+(2 \times 4)$

$\bar X$ = 70 + 8 = 78

Therefore, the value of the sample mean is 78.

3 0

3 years ago

What is the completely factored form of f of x equals x3 - 2x2 - 5x + 6

GalinKa [24]

Answer:

The completely factorized form is: (x - 1)(x + 2 )(x - 3)

Step-by-step explanation:

To find the solution, we use Ruffini's rule:

1 - 2 -5 + 6

We first divide by (x-1): 1 1 -1 -6

________________________

1 -1 -6 0

Then divide by (x + 2): - 2 -2 +6

_______________________

1 -3 0

Then, the rest of the division is: x - 3

Thus, the completely factorized form is: (x - 1) (x + 2 ) ( x - 3)

3 0

3 years ago

Read 2 more answers

Please help!! Will mark brainilest ☺️

FinnZ [79.3K]

Answer:

Step-by-step explanation:

Because there's no change in x so it has to be a straight line going through the y-axis.

Also for A and C, they don't even touch y = 2 so you can easily cross those out.

7 0

3 years ago

Pls help thx luv y’a

garik1379 [7]

Answer:

8.39958×10(raised to power of eight)

3 0

3 years ago