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siniylev [52]
3 years ago
14

The point A has coordinates (6,0).

Mathematics
1 answer:
marishachu [46]3 years ago
3 0

Answer:

(-6,0)

Step-by-step explanation:

1) First step is to reflect across the x-axis. Since it's ON the x-axis, it's y coordinate stays the same (0).

2) Now to flip over the y-axis, which is easy to calculate. As we can see it's "6" coordinate is what we need to change to "-6".

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Determine the maximized area of a rectangle that has a perimeter equal to 56m by creating and solving a quadratic equation. What
sveticcg [70]

Answer:

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Width of rectangle = 14 m

Step-by-step explanation:

Given:

Perimeter of rectangle is 56 m

To find: the maximized area of a rectangle and the length and width

Solution:

A function y=f(x) has a point of maxima at x=x_0 if f''(x_0)

Let x, y denotes length and width of the rectangle.

Perimeter of rectangle = 2( length + width )

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56=2(x+y)\\x+y=28\\y=28-x

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A = length × width

A=xy\\=x(28-x)\\=28x-x^2

Differentiate with respect to x

\frac{dA}{dx}=28-2x

Put \frac{dA}{dx}=0

28-2x=0\\2x=28\\x=14

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\frac{d^2A}{dx^2}=-2

At x = 14, \frac{d^2A}{dx^2}=-2

So, x = 14 is a point of maxima

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Area of rectangle:

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