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3 years ago

Plzzzzzz helpppp asapppp

Mathematics

2 answers:

ira [324]3 years ago

5 0

A 11.28. Because you have to setup

Amiraneli [1.4K]3 years ago

4 0

A 11.28 because you have to set up the cos20=x/12

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What is 2/3+1/6= in a fraction plz

svp [43]

2/3 + 1/6 =
4/6 + 1/6 =
5/6

7 0

3 years ago

Heather Pablo, and Shen sent a total of 123 text messages during the weekend. Heather sent 9 more messages than Pablo. Shen sent

Korolek [52]

Answer:

Heather sent 28, Pablo sent 19, and Shen sent 76.

Step-by-step explanation:

This will be your equation

123 = H (Heather) + P (Pablo) + S (Shen)

This is the extra stuff

P + 9 = H

4P = S

Substitute so there is only P then use that to solve for the rest

123 = P + 9 + P + 4P

Then solve

123 = 6P + 9

123 - 9 = 6P + 9 - 9

114 = 6P

19 = P

Then substitute for the extra equations

19 (P) + 9 = 28 (H)

19 (P) * 4 = 76

8 0

3 years ago

A ballasted roof is flat and covered with gravel to hold the roofing material in place. Adam plans to cover the roof in the diag

Yuri [45]

Answer:

$Area = 2,031ft^2$

Total weight of gravel on the roof = $24,372 pounds$

Step-by-step Explanation:

The area Adams planned to cover with gravel can be divided into 3 rectangles as shown in the diagram attached.

We would have 3 rectangles. See the attachment below to check out how we arrive at the dimensions of the 3 rectangles.

Area of rectangle = L*W

Area to be covered by gravel = area of rectangle 1 + area of rectangle 2 + area of rectangle 3

Area to be covered with gravel = $(30*17) + (13*9) + (52*27)$

$Area = (30*17) + (13*9) + (52*27) = 2,031ft^2$

Total weight of gravel on the roof = 12 pounds per square foot multiplied by total area of the roof to be covered = $12 * 2031 = 24,372 pounds$

5 0

3 years ago

The sum of the circumference of two circles is 38π cm and the sum of their areas is 193π cm². Calculate the radii of the circles

sdas [7]

Answer:

The radii of the circles are 12 cm and 7cm.

Step-by-step explanation:

Let the radii of the circles be $r_{1}\ and\ r_{2}$

Given:

Sum of circumference of two circles= 38π cm

Formula for circumference of a circle with radius r = 2πr

$2\pi r_{1}+2\pi r_{2}=38\pi \\r_{1}+r_{2}=19$ ------------1

Sum of areas of two circles= 193π cm²

Area of circle with radius r = πr²

$\pi r_{1}^{2}+\pi r_{2}^{2}=193\pi \\r_{1}^{2}+r_{2}^{2}=193$ -------2

Substituting r2 = 19 - r1 in equation 2 we get:

$r_{1}^{2}+(19-r_{1})^{2}=193\\2r_{1}^{2}-38r_{1}+168=0\\r_{1}^{2}-19r_{1}+84=0\\(r_{1}-12)(r_{1}-7)=0\\r_{1}=12\ or\ 7$

Then r2 = 19 - r1

$r_{2}=12\ or\ 7$

7 0

3 years ago

Emergency!

Lesechka [4]

Every single one of those expressions factor. When factored, this is what we have: $\frac{(3x-7)(x+3)}{(x+3)(x-2)} * \frac{(2x-7)(x+9)}{(3x-7)(2x+7)}$ . After canceling out like factors, what we are left with is this: $\frac{1x+9}{1x-2}$ . That means that b = 9, c = 1, and d = -2

4 0

3 years ago