Answer:
561
Explanation:
This is math so I got you.
This is just going to subtract 12 from 55 since we don't now when during her 12th year of age she started or when during her 55th year f age she ended.
55 - 12 = 43, so about 43 years. Also not going to account for leap years. So we are just going to say each year had 365 days. so 43 years and 365 days per year = 15695 days.
If her cycles were each about 28 days we divide the total number of days by 28 and that tells us about how many cycles there were.
15,695 / 28 = 560.5 which I will round to 561
561 cycles means 561 eggs if my biology knowledge is as accurate as I think it is.
Answer:
<u>C</u>. containing
- <u><em>egg albumen
</em></u>
- <u><em>protease
</em></u>
- <u><em>dilute hydrochloric acid</em></u>
Explanation:
A protease is a kind of peptidase enzyme that breaks down proteins into peptide molecules. As a digestive enzyme it is located in the lining of the stomach where, relative to the hydrochloric acid in digestive juices, the pH is usually low/ acidic.
<em>Enzymes speed up reaction rates by </em><em>providing alternative pathways</em>. By modifying the enzyme composition, supplying more collision energy, and changing the collisions between and the ratio of reactants, certain variables will increase the reaction rate.
Proteases function well at 37℃, the typical internal temperature of the human body- this temperature provides adequate energy for the reaction. Similarly, proteases require low pH for the correct configuration, and beyond this pH and temperature, they may become denatured or simply not function well as catalysts.
"
your answer is condensation because that is the process in the water cycle in which water is evaporated or changed into clouds.
For meiosis, this is in anaphase I. For the separation of sister CHROMATIDS in mitosis, this is anaphase. Either way, the separation of two whole chromosomes or two chromatids within one whole chromosome takes place during anaphase. This occurs after metaphase and before telophase and cytokinesis.
Answer : The dissociation constant of the PFK‑inhibitor complex is, 5 µM
Explanation :
The expression for reversible competitive inhibition when apparent Km affected by addition of the inhibitor is:
![K_m_a=K_m[1+\frac{I}{K_i}]](https://tex.z-dn.net/?f=K_m_a%3DK_m%5B1%2B%5Cfrac%7BI%7D%7BK_i%7D%5D)
where,
= apparent value = 52 µM
= Michaelis–Menten constant = 40 µM
I = inhibitor concentration = 1.5 µM
= dissociation constant of the PFK‑inhibitor complex
Now put all the given values in the above formula, we get:
![52\mu M=40\mu M[1+\frac{1.5\mu M}{K_i}]](https://tex.z-dn.net/?f=52%5Cmu%20M%3D40%5Cmu%20M%5B1%2B%5Cfrac%7B1.5%5Cmu%20M%7D%7BK_i%7D%5D)

Therefore, the dissociation constant of the PFK‑inhibitor complex is, 5 µM