The minimum number of socks that she needs to get such that a pair is always formed is 5.
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How many socks must she get to be ensured of having a pair?</h3>
We know that she has:
- 10 white socks.
- 10 black socks
- 10 brown socks
- 10 blue socks.
First, we need to compute the maximum number of socks she needs to take in such a case that no pair is formed.
That will be 4, and represents the case where:
1 white sock, 1 black sock, 1 brown sock, and 1 blue sock are drawn. At that point, no pairs are formed.
Now, if she draws another sock, a pair will always be formed.
From this, we conclude that if she draws 5 socks, always at least one pair will be formed.
If you want to learn more about combinations, you can read:
brainly.com/question/11732255
You can simplify it further to: 2n-1 over 3n-5
Y = T+3 (i)
T = H+2 (ii)
Y = 2*H (iiii)
T = H+2 therefore H = T-2
Substitute H=T-2 into (iii)
Y=2*H
Y=2*(T-2)
Y=2T-4
Now substitute that Y into (i)
(i) says Y = T+3
2T-4=T+3
2T-T-4=3
T-4=3
T=3+4
T=7
Then from (i) Y=T+3 = 7+3 =10
Y=10
And from (iii) Y=2*H
If Y = 10, then H = 5
-2a+2=22
3(a+4)-5(a-2)=22
3a+12-5a-10=22
-2a+12-10=22
-2a+2=22
I think the question is wrong!
It must be
x-4
___= 5
x+2
Answer: x - 4= 5x + 10
or,-10 -4 = 5x - x
or, -14=4x
or,-14/4= x
Therefore, x = -14/4
