200 times / 3 minutes = x times / 60 minutes
3x = 12000
x = 4000 times in an hour
A person's heart will beat 4000 times in an hour.
Hope this helps!! :)
Answer:
739
Step-by-step explanation:
a sub 92 = 11 + (92 - 1) * 8
a sub 92 = 11 + 728
a sub 92 = 739
Hello!
To find the fraction of the apartments that have not been scheduled to receive new carpet, we need first need find the number of apartments not receiving new carpet, by subtracting the total amount of apartments, by the 75 that have been scheduled.
120 - 75 = 45 apartments
Next, we need to create a fraction. Since 45 out of 120 apartments not are scheduled to get new carpeting, the fraction of these values is 45/120. This can be reduced to 3/8.
Therefore, your final answer is 45/120, simplified to 3/8.
55
To start to solve this problem we start by observing what information there is. We need y, to find y we have to know x. We need x to find y because all the angles in a triangle add up to 180. If we find x we can subtract the angles we know and get y. To find x we look and see that it is on a straight line, and on the other side of the line is 100. We know that a straight line is 180 degrees so we subtract 100 from 180 to get x. We now know x is 80, so now we minus 89 and 45 from 180. We get 55. This means that y is 55.
Hope this helps! Please make me the brainliest, it’s not necessary but appreciated, I put a lot of effort and research into my answers. Have a good day, stay safe and stay healthy.
Answer:
H0: μ ≤ 34
H1: μ > 34
The z-test statistic is ≈ 1.8
The critical z-score is 1.28
we fail to reject the null hypothesis H0: μ ≤ 34
Step-by-step explanation:
H0: μ ≤ 34
H1: μ > 34
The z-test statistic is calculated using the formula:
z=
where
- X is the average class size found in the sample (35.6)
- M is the mean according to the null hypothesis (34)
- s is the standard deviation for class size (9)
then z=
≈ 0.18
The critical z-score is 1.28 for α=0.10 (one tailed)
Because the test statistic is less than the critical value, do not reject the null hypothesis.