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Mekhanik [1.2K]
3 years ago
8

Mason sells life insurance policies. He earns a 12 percent commission on every policy he sells. He made the following sales this

week: Monday $425.00, Tuesday $694.25, Wednesday $296.14, Thursday $501.85, and Friday $358.76. What is his commission for the week?
Mathematics
1 answer:
scZoUnD [109]3 years ago
6 0

Answer: Mason made $185.00

Step-by-step explanation:

For the first 10 suits he made $12.50 each suit, then he made $20 for the additional 3.  (Just ignore the "suits part ._.)

250*.05=12.50

250*.08=20

12.50*10=125

3*20=60

125+60=185.

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Answer:

a) For this case the value of the significanceis \alpha=0.05 and \alpha/2 =0.025, we need a value on the normal standard distribution thataccumulates 0.025 of the area on each tail and we got:

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If the calculated statistic |z_{calc}| >1.96 we can reject the null hypothesis at 5% of significance

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c)z=\frac{0.85-0.733}{\sqrt{0.8(1-0.8)(\frac{1}{200}+\frac{1}{150})}}=2.708    

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Step-by-step explanation:

Data given and notation    

X_{1}=170 represent the number of people with the characteristic 1

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p_v represent the value for the test (variable of interest)  

\alpha=0.05 significance level given  

Concepts and formulas to use    

We need to conduct a hypothesis in order to check if is there is a difference between the two proportions, the system of hypothesis would be:    

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

We need to apply a z test to compare proportions, and the statistic is given by:    

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

a.State the decision rule.

For this case the value of the significanceis \alpha=0.05 and \alpha/2 =0.025, we need a value on the normal standard distribution thataccumulates 0.025 of the area on each tail and we got:

z_{\alpha/2} =1.96

If the calculated statistic |z_{calc}| >1.96 we can reject the null hypothesis at 5% of significance

b. Compute the pooled proportion.

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{170+110}{200+150}=0.8  

c. Compute the value of the test statistic.                                                                                              

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.    

Replacing in formula (1) the values obtained we got this:    

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