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2 years ago

6

Ok this is not a solve, more of a vocab question. Whats the term used for the number circled? Like is that called a coefficient

or something??

1 answer:

yanalaym [24]2 years ago

4 0

Answer:

I believe the term is the index number

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The width of a rectangle is 7x - 6 feet and the length is 3x + 7 feet. Find the perimeter of the rectangle.

aliina [53]

Answer:

P= 20x+2 ft

Step-by-step explanation:

________

I I

I I 3x + 7ft

________

7x - 6ft

P= (7x - 6 + 7x - 6) + (3x + 7 + 3x + 7)

= (14x - 12) + (6x + 14)

= 20x + 2 ft

8 0

2 years ago

The fifth term of an arithmetic sequence is 23 and the 12th term is 72? Determine the first three terms of the sequence and the

Arisa [49]

Answer:

the first term is a1

the distance between the numbers is d

we have:

a5 = a1 + 4d = 23

a12 = a1 + 11d = 72

so we have the equation:

a1 + 4d = 23

a1 + 11d = 72

=> a1 = -5

d = 7

=> an = -5 + 7(n - 1) = 7n - 12

with an = 7n - 12

=> a2 = 2

a3 = 9

so the first three terms is -5; 2; 9

6 0

3 years ago

PLS HELP:( !! What is an equation of the line

pychu [463]

Answer:

$y = \frac{3}{2} x + 8$

Step-by-step explanation:

The given equation is written in the form of y=mx+c (where m is the gradient and c is the y-intercept).

Thus, gradient of given equation= -⅔

The products of the gradient of perpendicular lines is -1.

(Gradient of line)(-⅔)= -1

Gradient of line

$= - 1 \div ( - \frac{2}{3} ) \\ = \frac{3}{2}$

Hence, m= $\frac{3}{2}$ .

Subst. m= $\frac{3}{2}$ into the equation:

$y = \frac{3}{2} x + c$

To find the value of c, substitute a pair of coordinates into the equation:

When x= -4, y= 2,

$2 = \frac{3}{2} ( - 4) + c \\ 2 = - 6 + c \\ c = 2 + 6 \\ c = 8$

Thus, the equation of the line is $y = \frac{3}{2} x + 8$ .

3 0

2 years ago

Read 2 more answers

A written description of -5a+3>1

Rudiy27

The sum of negative 5a and 3 is greater than 1.

8 0

3 years ago

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Help anyone can help me do the question 4,I will mark brainlest.

nasty-shy [4]

Answer:

Hello,

Step-by-step explanation:

$A=(1,2)\\B=(0,-1)\\\overrightarrow{AB}=((0,-1)-(1,2)=(-1,-3)\ ||\overrightarrow{AB}||^2=1+9=10\\\overrightarrow{BC}=((3,-2)-(0,-1)=(3,-1)\ ||\overrightarrow{BC}||^2=9+1=10\\\\Triangle\ is\ isosceles.\\\\\overrightarrow{AB}.\overrightarrow{BC}=(-1,-3)*\left[\begin{array}{c}3\\-1\end{array}\right] =-3+3=0\\\\Triangle \ is\ right.\\\\$

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2 years ago

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