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2 years ago

Please help Me Find The missing values in the ratio table then write equivalent ratios.

Mathematics

1 answer:

lara [203]2 years ago

6 0

3:8 = 12:x so multiply 8 by 4 which is 32 so 3:8 = 12:32. The next one is 3:8 = x:48 So for this, you can multiply 3 by 6 to get 18:48 as your answer.

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Describe the process for graphing the equation y =-1/2x- 1

AysviL [449]

the formula is y=mx+b

m is the slope

b is the y-intercept form

so the -1 is the y-intercept form. so you need to start at that point on the y axis. then the slope which is -1/2 comes into play. in my school we use rise/run. so from the point you marked at -1 you will go down 1 and to the right 2 points then where you stop is your next point (mark it) keep doing that. also go up the other way from the -1 point. go up 1 and to the left 2. then connect all of your points with a line. I hope this helped.

please chose this answer as brainliest

4 0

3 years ago

What is the missing polynomial?

german

Answer:

C. 40-4x-12x^2

Step-by-step explanation:

very simple

? – (20 – 4x – 5x2) = 20 – 7x2, so ? = 20 – 7x2 + (20 – 4x – 5x2)

? = 20 – 7x2 + (20 – 4x – 5x2)=20-7x²+20-4x-5x²=40-12x²-4x

7 0

3 years ago

Read 2 more answers

Will the following list have a large or small Standard Deviation?

jek_recluse [69]

Answer:

large

Step-by-step explanation:

3 0

3 years ago

Write an equation and solve. How opd am I if 400 reduced by 2 times my age is 244?

seropon [69]

Answer:

Step-by-step explanation:

x = your age

400 - 2x = 244

subtract 400 from both sides of the equation:

-2x = -156

divide both sides by -2:

x = 78

4 0

3 years ago

Read 2 more answers

For what values of θ on the polar curve r=θ, with 0≤θ≤2π , are the tangent lines horizontal? Vertical?

Bond [772]

Given that $r=\theta$ , then $r'=1$

The slope of a tangent line in the polar coordinate is given by:

$m= \frac{r'\sin\theta+r\cos\theta}{r'\cos\theta-r\sin\theta}$

Thus, we have:

$m= \frac{\sin\theta+\theta\cos\theta}{\cos\theta-\theta\sin\theta}$

Part A:

For horizontal tangent lines, m = 0.

Thus, we have:

$\sin\theta+\theta\cos\theta=0 \\ \\ \theta\cos\theta=-\sin\theta \\ \\ \theta=- \frac{\sin\theta}{\cos\theta} =-\tan\theta$

Therefore, the values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:

θ = 0

θ = 2.02875783811043

θ = 4.91318043943488

Part B:

For vertical tangent lines, $\frac{1}{m} =0$

Thus, we have:

$\cos\theta-\theta\sin\theta=0 \\ \\ \Rightarrow\theta\sin\theta=\cos\theta \\ \\ \Rightarrow\theta= \frac{\cos\theta}{\sin\theta} =\sec\theta$

Therefore, the values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are vertical are:

θ = 4.91718592528713

3 0

3 years ago