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VLD [36.1K]
3 years ago
15

What is the equation of the asymptote of the graph of y=3(4^x) A. x=4 B. x=0 C. y=3 D. y=0

Mathematics
1 answer:
kompoz [17]3 years ago
3 0
The asymptote cannot be x= because x can be any number. If you think about it, you can take a number to any exponent.
If x is a positive exponent, y is positive.
If x is a nevative exponent, y decreases, but is still positive. This is because a number to a negative exponent equals 1 over the number to the positive exponent. Thus, it is smaller, but still positive.
If x is 0, y is positive again because anything to the zero is positive 1.
There is no way y could be less than or equal to zero. So, there is an asymptote at y=0.
Also, set the equation equal to 0 and solve. You should end up with 4^x=0. Since no exponenent can make a number zero, this isn't possible, so y cannot equal zero.
Here is the graph for a visual:

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Solve for k.<br> 10<br> 1323<br> 3<br> 9<br> CAN U HELP PLEASE
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Step-by-step explanation:

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2 years ago
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find the equation of the sides of an isosceles right angled triangle whose vertex is (-2,-3) and the base is on the line x=0​
Serggg [28]

Answer:

AC:y=x-1  CB:y=-x-5 AB:x=0

Step-by-step explanation:

Consider the triangle. The base AB is on the line x=0, the vertex C is (-2,-3)

The side AC is equal to BC. The angle ACB is 90 degrees. If the base is on the line x=o, it is on the axis Y.Explore the distance from the point C to the AB

c(-2,-3), the distance to the axis Y is equal to the modul of the coordinate x (-2), it is 2. The coordinates of point projected by the point C to the axis Y is N(0,-3). The modul of the height is 2, the height of the isosceles triangle to the base is the bisectrix, so the angle BCA is 90/2=45degrees, CBA is 180-90-45=45 degrees too

the heigt CN is equal to side NB, NB=2

Suppose B is (0,y) (x=0 because the base is on this line)

THe modul of the vector NB is equal to sqrt ((0-0)^2+(y+3)^2)= 2

modul (y+3)= 2

y=-1 or y=-5

(0,-1), (0,-5) - two points, one of them (suppose B) is (0,-5) when A is (0,-1) (A is remote from the point N on the same distance with B, because AB is the median too)

Find CB and AC

Use the equation for AC

(x-0)/(-2-0)= (y+1)/(-3+1)

x/-2= (y+1)/-2

x=y+1

y=x-1

For CB

(x-0)/ (-2-0)= (y+5)/ (-3-(-5))

x/-2= (y+5)/2

-x=y+5

y=-x-5

7 0
2 years ago
Is the answer: -5, -2, 3, 5?
lara31 [8.8K]

Answer:

Y= -1 and Y = -5

Step-by-step explanation:

To find the Value of Y need to find where the Line(s) Cross they Vertical Axis.

5 0
3 years ago
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Help help help help help helo help
Kay [80]

Answer:

50.27

452.39

0.79

Step-by-step explanation:

A=πr2=π·42≈50.26548

A=πr2=π·122≈452.38934

A=πr2=π·0.52≈0.7854

8 0
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