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VLD [36.1K]
2 years ago
15

What is the equation of the asymptote of the graph of y=3(4^x) A. x=4 B. x=0 C. y=3 D. y=0

Mathematics
1 answer:
kompoz [17]2 years ago
3 0
The asymptote cannot be x= because x can be any number. If you think about it, you can take a number to any exponent.
If x is a positive exponent, y is positive.
If x is a nevative exponent, y decreases, but is still positive. This is because a number to a negative exponent equals 1 over the number to the positive exponent. Thus, it is smaller, but still positive.
If x is 0, y is positive again because anything to the zero is positive 1.
There is no way y could be less than or equal to zero. So, there is an asymptote at y=0.
Also, set the equation equal to 0 and solve. You should end up with 4^x=0. Since no exponenent can make a number zero, this isn't possible, so y cannot equal zero.
Here is the graph for a visual:

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Answer:

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Step-by-step explanation:

We have,

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The circumference of a circular shape is given by :

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r=\dfrac{C}{2\pi}\\\\r=\dfrac{21.4}{2\times 3.14}\\\\r=3.4\ \text{inches}

Area of this plate is given by :

A=\pi r^2\\\\A=\pi (3.4)^2\\\\A=36.31\ \text{inches}^2

So, the area of this plate is 36.31\ \text{inches}^2.

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