Take the derivative:
g’(x) = 12x^3 - 24x^2
Set equal to zero and solve:
0 = 12x^3 - 24x^2
0 = 12x^2 (x - 2)
x = 0 or x = 2
Plug back into original
g(0) = 3(0^4) - 8(0^3)
g(0) = 0 - 0
g(0) = 0
g(2) = 3(2^2) - 8(2^3)
g(2) = 3(4) - 8(8)
g(2) = 12 - 64
g(2) = -52
There is an absolute max at (0,0) or when x = 0
Answer:
Step-by-step explanation:
<u>Exponential function:</u>
<u>Ordered pairs given:</u>
<u>Substitute x and y values to get below system:</u>
<u>Divide the second equation by the first one and solve for b:</u>
- 80/10 = b³
- b³ = 8
- b = ∛8
- b = 2
<u>Use the first equation and find the value of a:</u>
<u>The function is:</u>
Answer:
x>6
Step-by-step explanation:
2x > 16-4
x > 12/2
x > 6
Answer:
14256
Step-by-step explanation:
