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Katyanochek1 [597]
2 years ago
13

Please provide a answer

Mathematics
1 answer:
Schach [20]2 years ago
8 0

Answer:

uhh, look it up

Step-by-step explanation:

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The derivative of f(x) = e^xinx​
aksik [14]

Answer:

e^xsinx · (sinx+xcosx)

Step-by-step explanation:

f'(x)=e^xsinx · (xsinx)'= e^xsinx · (sinx+xcosx)

4 0
3 years ago
Discuss the continuity of the function on the closed interval.Function Intervalf(x) = 9 − x, x ≤ 09 + 12x, x > 0 [−4, 5]The f
quester [9]

Answer:

It is continuous since \lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)

Step-by-step explanation:

We are given that the function is defined as follows f(x) = 9-x, x\leq 0 and f(x) = 9+12x, x>0 and we want to check the continuity in the interval [-4,5]. Note that this a piecewise function whose only critical point (that might be a candidate of a discontinuity)  x=0 since at this point is where the function "changes" of definition. Note that 9-x and 9+12x are polynomials that are continous over all \mathbb{R}. So F is continous in the intervals [-4,0) and (0,5]. To check if f(x) is continuous at 0, we must check that

\lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x) (this is the definition of continuity at x=0)

Note that if x=0, then f(x) = 9-x. So, f(0)=9. On the same time, note that

\lim_{x\to 0^{-}} f(x) = \lim_{x\to 0^{-}} 9-x = 9. This result is because the function 9-x is continous at x=0, so the left-hand limit is equal to the value of the function at 0.

Note that when x>0, we have that f(x) = 9+12x. In this case, we have that

\lim_{x\to 0^{+}} f(x) = \lim_{x\to 0^{+}} 9+12x = 9. As before, this result is because the function 9+12x is continous at x=0, so the right-hand limit is equal to the value of the function at 0.

Thus, \lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)=9, so by definition, f is continuous at x=0, hence continuous over the interval [-4,5].

5 0
3 years ago
Read 2 more answers
2.
exis [7]

Answer:

36-k

Step-by-step explanation:

5 0
3 years ago
5400/10251 in simplest form<br> 5400/10251 as a decimal number<br> 5400/10251 as a percentage
soldier1979 [14.2K]
600/1139 (5400/10251 Simplest)
0.62677787 (decimal)
52.67778753 % (percent)

I think
4 0
3 years ago
21 is what percent of 40?
elena-s [515]

1. We assume, that the number 40 is 100% - because it's the output value of the task.

2. We assume, that x is the value we are looking for.

3. If 100% equals 40, so we can write it down as 100%=40.

4. We know, that x% equals 21 of the output value, so we can write it down as x%=21.

5. Now we have two simple equations:

1) 100%=40

2) x%=21

where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:

100%/x%=40/21

6. Now we just have to solve the simple equation, and we will get the solution we are looking for.


7. Solution for 21 is what percent of 40


100%/x%=40/21

(100/x)*x=(40/21)*x       - we multiply both sides of the equation by x

100=1.90476190476*x       - we divide both sides of the equation by (1.90476190476) to get x

100/1.90476190476=x

52.5=x

x=52.5


now we have:

21 is 52.5% of 40

6 0
3 years ago
Read 2 more answers
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