Answer:
1 3/7 quarts should be drained off and replaced with pure antifreeze.
1 3/7 ≈ 1.4286
Current amount of antifreeze in quarts is -
30/ 100 × 10 = 3
40% ---> 4 quarts
Let the amount drained of and replaced with antifreeze be x-
The amount left after draining off is 10 − x.
The amount of antifreeze is 30/ 100 (10−x).
30/100(10-x)+x=4
3-3/10x+x=4
3+x(1-3/10)=4
x=1*10/7=1 3/7 quarts
check;
10- 1 3/7 = 8 4/7
=(30/100*8 4/7)+1 3/7
=(3/10 * 60/7) + 10/7
=3*6/7 + 10/7
=28/7
=4
4 liters of pure antifreeze is mixed into 10 quarts.
Put one dot on (0,-2) , (4,0), (-4,-4) connect the dots that is your graph line.
Slope is 1/2 and you is -4
Answer: (-9,-1)
Step-by-step explanation:
For this case, the arithmetic sequence is given by:
an = 17n-1
Let's check it:
First week:
n = 1:
a1 = 17 (1) -1
a1 = 17-1
a1 = 16
Second week:
n = 2:
a2 = 17 (2) -1
a2 = 34-1
a2 = 33
Third week:
n = 3:
a3 = 17 (3) -1
a3 = 51-1
a3 = 50
Answer:
the explicit rule for the arithmetic sequence that defines the number of boxes of cereal sold in week n is:
an = 17n-1
Ratio = 5:2:3:8
Sum of all internal angles = 360°
5x + 2x + 3x + 8x = 360°
18x = 360°
x = 20°
Therefore,
5x = 100°
2x = 40°
3x = 60°
8x = 160°
5:2:3:8 :: 100:40:60:160.
