Answer:
Step-by-step explanation:
Here is the exact construction of √40 using Pythagorean 's theorem
<span>I will assume the more likely selection of $10 per sandal as opposed to $0.05 per sandal.
So with the formulas
c = 1000 + 5x
r = 75x - 0.4x^2
Sandals Cost Revenue Profit or Loss
0 $1,000.00 $0.00 -$1,000.00
1 $1,005.00 $74.60 -$930.40
2 $1,010.00 $148.40 -$861.60
3 $1,015.00 $221.40 -$793.60
4 $1,020.00 $293.60 -$726.40
5 $1,025.00 $365.00 -$660.00
6 $1,030.00 $435.60 -$594.40
7 $1,035.00 $505.40 -$529.60
8 $1,040.00 $574.40 -$465.60
9 $1,045.00 $642.60 -$402.40
10 $1,050.00 $710.00 -$340.00
11 $1,055.00 $776.60 -$278.40
12 $1,060.00 $842.40 -$217.60
13 $1,065.00 $907.40 -$157.60
14 $1,070.00 $971.60 -$98.40
15 $1,075.00 $1,035.00 -$40.00
16 $1,080.00 $1,097.60 $17.60
17 $1,085.00 $1,159.40 $74.40
18 $1,090.00 $1,220.40 $130.40
19 $1,095.00 $1,280.60 $185.60
20 $1,100.00 $1,340.00 $240.00
As you can see 16 sandals and up is profitable.
At what production levels will the company lose money?
a. between 0 and 10 or between 150 and 190 pairs, inclusive
150 and 190
c. between 10 and 20 or between 50 and 100, inclusive
If you add up the profit between 10 and 20 you will get $-484 so 50 and 100
b. between 0 and 15 or between 160 and 200 pairs, inclusive
160 and 200
d. between 15 and 35 or between 75 and 125, inclusive
Neither 15 and 35 or 75 and 125 will lose money.</span>
Answer:
1. 1343 years
2. 9 hours
3. 39 years
Step-by-step explanation:
1. Given, half-life of carbon = 5730 years.
∴ λ = 0.693/half-life of carbon = 0.693/5730 = 0.000121
If N₀ = 100 then N = 85
Formula:- N = N₀*e^(-λt)
∴ 85 = 100 * e^(-0.000121t)
∴㏑(-0.85)=-0.000121t
∴ t = 1343 years
2. Given half-life of aspirin = 12 hours
λ = 0.693/12 = 0.5775
Also N₀ = 100 then 70 will disintegrate and N = 30 will remain disintegrated.
∴ 70 = 100 *e^(-0.05775t)
0.70 = e^(-0.05775t)
㏑(0.70) = -0.05775t
∴ t = 9 hours
3. The population of the birds as as A=A₀*e^(kt)
Given that the population of birds fell from 1400 from 1000, We are asked how much time it will take for the population to drop below 100, let that be x years.
The population is 1400 when f = 0, And it is 1000 when f = 5
We can write the following equation :
1400 = 1000e^(5t).
∴1400/1000 = e^(5k)
∴ k = ㏑(1.4)/5
We need to find x such that 1400/100 = e^(xk)
14 = e^(xk)
∴ x = 39 years
Answer:
One possible answer is:
f(x) = (2/x) + 3 and g(x) = x².
Step-by-step explanation:
Explanation:
We are to write this equation as y = f(g(x)). This means we want it to be a composite of functions; in f(x), we take the value of g(x) and use in place of x.
If we let g(x) = x², this means everywhere we see an x in f(x), we will replace it with x². To make our equation y = 2/x² + 3, working backward we would substitute x for x²; this would give us f(x) = 2/x + 3.
Answer:
v= -2
Step-by-step explanation:
2v + 7 = 3
(-7 both sides)
2v = -4
(divide bu 2 on both sides)
v = -2
hope this helps!!!!! :)
