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adoni [48]
3 years ago
9

How is matter and energy conserved in this chemical reaction?

Chemistry
1 answer:
finlep [7]3 years ago
5 0

Answer:

The ratio of reactants and products in a chemical reaction is called chemical stoichiometry . Stoichiometry depends on the fact that matter is conserved in chemical processes, and calculations giving mass relationships are based on the concept of the mole . One mole of any element or compound contains the same number of atoms or molecules, respectively, as one mole of any other element or compound.

Explanation:

Hope this helps :)

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Answer and Explanation: 

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2 years ago
What is Chromatography?
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Hope this helps :)

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3 years ago
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Balance each skeleton reaction, use Appendix D to calculate E°cell, and state whether the reaction is spontaneous:(b) Hg₂²⁺(aq)
Olegator [25]

The given reaction is not spontaneous.

We must recognize changes in oxidation states that take place across elements in order to balance these equations. To accomplish this, keep in mind following guidelines:

A neutral element on its own has an oxidation number of zero.For a neutral molecule, the total number of oxidations must be zero.The net charge of an ion is equal to the sum of its oxidation numbers.In a compound: hydrogen prefers +1, oxygen prefers -2, fluorine prefers -1.In a compound with no oxygen present the other halogens will also prefer -1.

One of the mercury atoms is oxidized from +1 to +2 in the simple aqueous ion, for a loss of 1 electron.

Oxidation half-reaction:

0.5 Hg^{2+} _{2} (aq) →Hg^{2+} (aq) + 1e^-

E^o _{ox} = - 0.92 V

The other mercury is reduced from +1  to zero in mercury metal, for a gain of 1 electron.

Reduction half-reaction:

0.5 Hg^{2+} _{2} (aq) + 1 e^- →Hg(l)

E^o _{red} = 0.85V

This is a disproportionation redox reaction !

Net reaction:

Hg^{2+} _{2} (aq) →Hg^{2+} (aq) + Hg (l)

E^o _{cell} = 0.85 - 0.92 = -0.07V

The cell potential is negative so this reaction is NOT spontaneous.

To learn more about the non spontaneous reaction please click on the link brainly.com/question/20358734

#SPJ4

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