Molecules of sodium oxide will be created if 187 grams of oxygen reacts with excess sodium will be 7.04 × 10 ²⁴ molecules.
Sodium oxide is Na₂O which is formed due to the reaction of sodium and oxygen.
Given,
Balanced chemical equation is :
4 Na(s) + O₂ (g) → 2Na₂O (s)
Now, the Mole ratio of O₂ and Na₂O is 1 mol O₂: 2 mol Na₂O
Molar mass O₂ = 32.00 g/mol
Now, let's find out the Number of moles of O₂ present in 187 grams of oxygen,
Number of moles of O₂ = Given mass in grams / molar mass of O₂
Number of moles of O₂ = 187 g / 32.00 g/mol
Number of moles of O₂ = 5.844 mol
Since, we know the Proportion is 1 mol O₂ : 2 mol Na₂O
Now, Number of moles of Na₂O required is,
2 mol Na₂O / 1 mol O₂ = 5.844 mol O₂ / x
x = 5.844 mol O₂ (2 mol Na₂O / 1 mol O₂)
x = 11.688 mol Na₂O
To calculate the Number of molecules of sodium oxide,
Number of molecules = Number of moles × Avogadro's number
Number of molecules = 11.688 mol × 6.022 × 10²³ molecules/mol =
Number of molecules = 7.04 × 10 ²⁴ molecules
Hence, the Number of molecules of sodium oxide required is 7.04 × 10²⁴ molecules.
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