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melomori [17]
2 years ago
8

A sugar crystal contains approximately 1. 9×1017 sucrose (c12h22o11c12h22o11) molecules. part a what is its mass in mgmg ? expre

ss your ans
Chemistry
1 answer:
yKpoI14uk [10]2 years ago
4 0

Sucrose is a disaccharide, which is a sugar molecule formed from two monosaccharides. In this case, the two monosaccharides are fructose and glucose.

Answer and Explanation: 

The number of molecules a" role="presentation" style="display: inline-block; line-height: 0; text-indent: 0px; text-align: left; text-transform: none; font-style: normal; font-weight: 400; font-size: 16.66px; letter-spacing: normal; overflow-wrap: normal; word-spacing: 0px; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; margin: 0px; padding: 1px 0px; color: rgb(0, 0, 0); font-family: "Open Sans", "Helvetica Neue", Helvetica, Arial, sans-serif; font-variant-ligatures: normal; font-variant-caps: normal; orphans: 2; widows: 2; -webkit-text-stroke-width: 0px; text-decoration-thickness: initial; text-decoration-style: initial; text-decoration-color: initial; position: relative;">aa is related to a quantity of moles n" role="presentation" style="display: inline-block; line-height: 0; text-indent: 0px; text-align: left; text-transform: none; font-style: normal; font-weight: 400; font-size: 16.66px; letter-spacing: normal; overflow-wrap: normal; word-spacing: 0px; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; margin: 0px; padding: 1px 0px; color: rgb(0, 0, 0); font-family: "Open Sans", "Helvetica Neue", Helvetica, Arial, sans-serif; font-variant-ligatures: normal; font-variant-caps: normal; orphans: 2; widows: 2; -webkit-text-stroke-width: 0px; text-decoration-thickness: initial; text-decoration-style: initial; text-decoration-color: initial; position: relative;">nn of any substance by Avogadro's number {eq}N_A = \rm 6.022\times...

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Consider the following equation: K + Br → KBr. How many grams of KBr can you make with 1.25g of K?
Dmitry [639]

Answer:

\fbox{3.81 \: grams}

Explanation:

First consider the mol to mol ratio, the mol of a substance is simply the count of atoms in respect to avagadros number (approx. 6.02 × 10²³ molecules) in the period table. 1 mol of an element is simply it's mass count in the periodic table.

5 0
3 years ago
How many oxygen molecules in 2.3x10-⁸g of molecular oxygen ​
cluponka [151]

Answer:

6.321 × 10^22

Explanation:

Mass of Oxygen =

3.36

g

Molar mass of oxygen (

O

2

) = 16 x 2 =

32

g

m

o

l

−

Total molecules in oxygen = Mass in grams/Molar mass x

N

A

=

3.36

32

x

6.02

x

10

23

=

6.321

x

10

22

Note:

N

A

(Avagadro's number) =

6.02

x

10

23

Hope it helps...

3 0
3 years ago
Label the slightly negative and slightly positive parts of the water molecule. Use this illustration to explain polarity.
Daniel [21]
The water molecule is a polar molecule which would mean that there is an uneven distribution of charges. Each molecule of water has partial positive and partial negative end.  The partial positive charges is found in the H atoms while the partial negative is at the O atom. This is due to the the unequal sharing of the electrons.
4 0
3 years ago
1.How many grams of zinc Zn and oxygen O2 will be needed to form 324 grams of ZnO after the reaction?
Murrr4er [49]

Answer: pretty sure its 0.214 moles * 40.3g/mole = 8.6g (2 sig figs) of MgO, and

0.035 moles * 40.3g/mole = 1.4g of MgO

Explanation:

6 0
3 years ago
Which of the following would force the reaction to favor the products? CaCO3(s) + 2H3O(aq) + Ca(aq) + 3H2O(1) + CO2(g) A) Removi
iVinArrow [24]

Answer: Option (C) is the correct answer.

Explanation:

As the given reaction is as follows.

     CaCO_{3}(s) + 2H_{3}O^{+}(aq) \rightleftharpoons Ca^{2+}(aq) + 3H_{2}O(l) + CO_{2}(g)

According to Le Chatelier's principle, any disturbance caused in an equilibrium reaction will shift the equilibrium in a direction that will oppose the change.

Hence, in order to favor the formation of products when we remove CO_{2} then there will occur decrease in it's concentration.

As CO_{2} is forming on the product side and equilibrium will shift in the direction where there is less stress.

Hence, then equilibrium will shift in the forward direction, that is, on the products side.

Thus, we can conclude that removing CO_{2} as it is formed would force the reaction to favor the products.

3 0
3 years ago
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